You can start this by setting up two vectors starting at the origin.
Vector 1 has coordinates of (-57,0) since in the east direction.
Vector 2 has coordinates of (0,13) because going north.
Starting from the origin, plot the two points, which will give you two sides of a triangle.
You can use pythagorean theorem to solve for the magnitude of the velocity. And you can find the angle by arctan(y/x)
Pythagorean would produce 58.46m/s
Answer:
The size of the force developing inside the steel rod is 32039.28 N
Explanation:
Given;
length of the steel rod, L = 1.55 m
cross sectional area of the steel, A = 4.89 cm²
temperature change, ∆T = 28.0 K
coefficient of linear expansion for steel, α = 1.17 × 10⁻⁵ 1/K
Young modulus of steel, E = 200.0 GPa.
Extension of the steel is given as;
α ∆T L = FL / AE
α ∆T = F/AE
F = AEα ∆T
F = ( 4.89 x 10⁻⁴)(200 x 10⁹)(1.17 × 10⁻⁵)(28.0 K)
F = 32039.28 N
Therefore, the size of the force developing inside the steel rod when its temperature is raised, is 32039.28 N
The answer is 6.no got it right
