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xeze [42]
3 years ago
15

Which of these is a relation ​

Mathematics
1 answer:
Roman55 [17]3 years ago
7 0

Answer:

Graph A

Step-by-step explanation:

For a relation to be said to be a function, each x-value must have exactly one y-value assigned to it. That is, no domain value has two different range value assigned to it.

Therefore, graph A is a function, because exactly 1 range value is assigned to each domain value.

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WdkNEIOEWHDEIWDHWWD/
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Answer:

ok brainliest pls

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Ayuda plis es para hoy.​
Readme [11.4K]

Answer:

8.29

Step-by-step explanation:

Cada linea representa ,1

y como es la ultima linea de las 9 antes del 8,3 la respuesta es 8.29

7 0
3 years ago
A farmer is planning a rectangular area for her chickens. the area of the rectangle will be 450 square feet. three sides of the
Leokris [45]
Let x represent the length in feet of the area along the barn wall. Then the width of the area (out from the wall) will be 450/x, and the total cost of fence will be
  cost = 5*(x +2*450/x)

A graphing calculator shows the minimum of the cost function is where x=30.

In order to minimize the cost of fencing, the fourth side should be 30 ft long.

5 0
3 years ago
What is the inverse of the function f(x) = 2x + 1?
soldier1979 [14.2K]

Answer: The inverse of the linear function f(x)=2x+1 is f^(-1) (x) = (1/2)x-1/2


Solution

f(x)=2x+1

y=f(x)

y=2x+1

Isolating x: Subtracting 1 both sides of the equation:

y-1=2x+1-1

y-1=2x

Multiplying both sides of the equation by 1/2:

(1/2)(y-1)=(1/2)2x

(1/2)y-1/2=x

x=(1/2)y-1/2

Changing "x" by "f^(-1) (x)" and "y" by "x":

f^(-1) (x) = (1/2)x-1/2

8 0
3 years ago
El tamaño de cierto cultivo de bacterias se multiplica por 2 cada 30 minutos. Si suponemos que el cultivo tiene inicialmente 256
Oduvanchick [21]

Answer:

La población de bacterias después de tres horas es de 2^{14} bacterias.

Step-by-step explanation:

En este enunciado observamos un caso de progresión geométrica, en donde la población de bacterias se duplica cada treinta minutos, es decir:

\frac{p(n\cdot\Delta t)}{p(0)} = 2^{n} (1)

Donde:

\Delta t - Intervalo de tiempo requerido para el incremento geométrico de la población, en minutos.

n - Número de períodos para incremento geométrico, sin unidad.

Sabemos que la población inicial de bacterias es 256 y que 3 horas son 6 veces 30 minutos. Entonces, tenemos la siguiente razón:

\frac{p(6\cdot \Delta t)}{p(0)} = 2^{6} (2)

Si sabemos que p(0) = 256, entonces p(6\cdot \Delta t) es:

p(6\cdot \Delta t) = 2^{6}\cdot p(0)

p(6\cdot \Delta t) = 2^{6}\cdot (256)

p(6\cdot \Delta t) = 2^{6}\cdot 2^{8}

p(6\cdot \Delta t) = 2^{14}

La población de bacterias después de tres horas es de 2^{14} bacterias.

4 0
3 years ago
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