All categories

3 years ago

An example of an action and reaction is sitting on a chair. Your body pushes down on the chair because of the force of what?

1 answer:

8 0

Your body is pushing down on a chair because it is being attracted by gravity, the reason that your body is not moving down because there is a normal force acting on your body; together the net force of weight (m*g) and normal force is equal to zero

You might be interested in

Three sticks are arranged to form a right triangle. If the lengths of the three sticks are 0.47 m, 0.62 m and 0.78 m, what are t

DanielleElmas [232]

Your answer is D) 90, 53, and 37.

5 0

2 years ago

Can there be situation when velocity is constant but speed is not

klasskru [66]

Answer:

no I don’t think there can be so my answer is No.

Okay then yes sorry that I must have gotten it wrong before.

Explanation:

4 0

3 years ago

Read 2 more answers

You have a stopped pipe of adjustable length close to a taut 62.0 cmcm, 7.25 gg wire under a tension of 4710 NN. You want to adj

Oksana_A [137]

Answer:

6 cm long

Explanation:

F = 4110N

Vo(speed of sound) = 344m/s

Mass = 7.25g = 0.00725kg

L = 62.0cm = 0.62m

Speed of a wave in string is

V = √(F / μ)

V = speed of the wave

F = force of tension acting on the string

μ = mass per unit density

F(n) = n (v / 2L)

L = string length

μ = mass / length

μ = 0.00725 / 0.62

μ = 0.0116 ≅ 0.0117kg/m

V = √(F / μ)

V = √(4110 / 0.0117)

v = 592.69m/s

Second overtone n = 3 since it's the third harmonic

F(n) = n * (v / 2L)

F₃ = 3 * [592.69 / (2 * 0.62)

F₃ = 1778.07 / 1.24 = 1433.927Hz

The frequency for standing wave in a stopped pipe

f = n (v / 4L)

Since it's the first fundamental, n = 1

1433.93 = 344 / 4L

4L = 344 / 1433.93

4L = 0.2399

L = 0.0599

L = 0.06cm

L = 6cm

The pipe should be 6 cm long

6 0

3 years ago

At an outdoor market, a bunch of bananas is set on a spring scale to measure the weight. The spring sets the full bunch of banan

olga55 [171]

Answer:

Mass of banana is $1.12$ Kg

Explanation:

Step 1: Determine the equation of speed of an object moving in an harmonic motion

Speed of moving in an harmonic motion is given by

$v = \sqrt{\frac{k}{m} (A^2 -x^2)} \\$

Here, v represents the speed of the object in harmonic motion, k is the springs constant, m is the mass of the object, A is the amplitude, and x is the position.

In this question , $x = 0$ because only at this position maximum speed occurs