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Phoenix [80]
3 years ago
8

1. If you add air to a flat tire through a single small entry hole, why does the air spread out to fill the tire?

Physics
1 answer:
ikadub [295]3 years ago
7 0

Answer:

The tire fills up just like anything else that holds air when u pump a ball or tire up it fills all the way up cause it is a small confined space and after filling it with air the atoms of the air fill the tire up

Explanation:

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A space station in the shape of a 100 m-diameter (50m radius) wheel is spinning so as to impart a linear tangential speed of 22.
zalisa [80]

Answer:

correct option is b. 31.3 m/s

Explanation:

given data

artificial gravity a1 = 1 g

artificial gravity a2 = 2 g

diameter = 100 m

radius  r= 50 m

speed v1 = 22.1 m/s

solution

As acceleration is  ∝ v²

so we can say

\frac{a2}{a1} = \frac{v2}{v1}    .....................1

put here value

\frac{2}{1} = \frac{v2}{22.1}  

solve it

v2 = \sqrt{2 } × 22.1

v2 = 31.25 m/s

so correct option is b. 31.3 m/s

4 0
3 years ago
Sue and jenny kick a soccer ball at exactly the same time. sue's foot exerts a force of 57.6 n to the north. jenny's foot exerts
Alika [10]
It is 17.58 my friennnd
8 0
3 years ago
Which event in a solar cell uses the photoelectric effect?
musickatia [10]

Answer:

Light shone on metal expulses electrons from its surface. This phenomenon is the photoelectric effect, and the electrons are called photoelectrons. Experiments indicate that by increasing light frequency, the kinetic energy of the photoelectrons increases, and by intensifying the light, the current increases

4 0
2 years ago
Read 2 more answers
What is the kinetic energy of a 1200 kg object that is moving at a speed of 24m/s?
n200080 [17]
Here, K.E. = 1/2 * mv²

So, K.E. = 1/2 * (1200) * (24)²

K.E. = 1/2 * 1200 * 576

K.E. = 600 * 576

K.E. = 345,600 J

Hope this helps!
6 0
3 years ago
You push a heavy crate out of a carpeted room and down a hallway with a waxed linoleum floor. While pushing the crate 2.5 m out
Alinara [238K]

Answer:

W = 1562.5 J

Explanation:

Path 1:

W₁ = F₁*d₁ = 385 N * 2.5 m = 962.5 J

Path 2:

W₂ = F₂*d₂ = 130 N * 10 m = 1300 J

Path 3:

W₃ = F₃*d₃ = (-350 N) * 2 m = - 700 J  (opposite to the motion)

We get

W = W₁ + W₂ + W₃ = 962.5 J + 1300 J + (- 700 J) = 1562.5 J

3 0
3 years ago
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