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dimaraw [331]
3 years ago
11

A 100 hz sound wave is traveling through the air. if we increase the frequency to 200 hz, this will _____ the wavelength. a 100

hz sound wave is traveling through the air. if we increase the frequency to 200 hz, this will _____ the wavelength. increase decrease not change
Physics
1 answer:
yanalaym [24]3 years ago
4 0
The correct answer is "decrease":
<span>A 100 hz sound wave is traveling through the air. if we increase the frequency to 200 hz, this will INCREASE the wavelength.

Let's see why. The basic relationship between frequency and wavelength of a wave is
</span>\lambda= \frac{v}{f}
<span>where
v is the speed of the wave
f its frequency
</span>\lambda its wavelength
<span>
We can see from this equation that, if the frequency is increased, if the speed of the wave does not change (and this is the case), then the wavelength of the wave must decrease, since the ratio </span>\frac{v}{f} becomes smaller.
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Serga [27]

we know that center of mass is given as

r = (m₁ r_{1x} + m₂ r_{2x})/(m₁ + m₂)

taking derivative both side relative to "t"

dr/dt = (m₁ dr_{1x}/dt + m₂ dr_{2x}/dt)/(m₁ + m₂)

v = (m₁ v_{1x} + m₂ v_{2x})/(m₁ + m₂)

taking derivative again relative to "t" both side

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3 years ago
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Suppose that a baseball is tossed up into the air at an initial velocity 1818​​\text{ m/s} m/s​. The height of the baseball at t
olga2289 [7]

Answer:

13.1 m/s

Explanation:

Given that a baseball is tossed up into the air at an initial velocity 18 m/s​. The height of the baseball at time t​ in seconds is given by h(t) = 18t−4.9t 2 ​​​​​ (in meters).

a) What is the average velocity for [1,1.5]​?

To calculate the velocity travelled by the ball, differentiate the function.

dh/dt = 18 - 9.8t

Substitute t for 1 in the above Differential function

dh/dt = 18 - 9.8 (1)

But dh/dt = velocity

V = 18 - 9.8

V = 8.2 m/s

Average velocity = ( U + V ) / 2

Average velocity = (18 + 8.2)/2

Average velocity = 26.2/2

Average velocity = 13.1 m/s

5 0
3 years ago
A pool ball moving 1.33 m/s strikes an identical ball at rest. Afterward, the first ball moves 0.750 m/s at a 33.30 angle. What
kramer

Explanation:

We need to apply the conservation law of linear momentum to two dimensions:

Let p_{1} = momentum of the 1st ball

p_{2} = momentum of the 2nd ball

In the x-axis, the conservation law can be written as

(p_{1} \cos \theta_{1})_{i} + (p_{2} \cos \theta_{2})_{i} = (p_{1} \cos \theta_{1})_{f} + (p_{2} \cos \theta_{2})_{f}

or

(m_{1}v_{1})_{i}= (m_{1}v_{1}\cos \theta_{1})_{f} + (m_{2}v_{2}\cos \theta_{2})_{f}

Since we are dealing with identical balls, all the m terms cancel out so we are left with

(v_{1})_{i} = (v_{1})_{f}\cos \theta_{1} +  (v_{2})_{f}\cos \theta_{2}

Putting in the numbers, we get

1.33 = (0.750) \cos(33.30)  + (v_{2})_{f} \cos \theta_{2}

=  > (v_{2})_{f} \cos \theta_{2} = 0.703

In the y-axis, there is no initial y-component of the momentum before the collision so we can write

0 = (v_{1}\sin \theta_{1})_{f} + (v_{2}\sin \theta_{2})_{f}

or

=  > (v_{2})_{f} \sin \theta_{2} = (0.750) \sin(33.30)  = 0.412

Taking the ratio of the sine equation to the cosine equation, we get

\frac{ \sin \theta _{2}}{ \cos \theta_{2} }  =  \tan \theta_{2}  =  \frac{0.412}{0.703}  = 0.586

or

\theta_{2}  =  { \tan}^{ - 1} (0.586) = 30.4

Solving now for (v_{2})_{f},

(v_{2})_{f}  =  \frac{0.412}{ \sin(30.4) }  = 0.815 \:  \frac{m}{s}

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Answer:

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Answer:

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Explanation:

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