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3 years ago

If y varies directly as x and k=8 , find x when y =8

Mathematics

2 answers:

Tju [1.3M]3 years ago

8 0

Answer:

x = 1

Step-by-step explanation:

Given that y varies directly as x then the equation relating them is

y = kx ← k is the constant of variation

here k = 8, thus

y = 8x ← equation of variation

When y = 8, then

8x = 8 ( divide both sides by 8 )

x = 1

mixas84 [53]3 years ago

8 0

For this case we have that the variables x and y vary directly according to the following constant of proportionality.

$k = 8$

Then, the equation would be:

$y= kx$

Substituting the value of y, we have the value of x

$\frac{8}{8}=x\\x=1$

Thus, $x =1\ when\ y = 8,$ according to the given proportionality constant.

Answer:

$x = 1$

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Nuts.com sells raw almonds for $10 per pound and roasted pistachios for $12 per pound. Christopher spends $70, before taxes and

galben [10]

Answer:

second equation

Step-by-step explanation:

10a + 12p = 70 (10 goes with almonds [a], 12 goes with pistachios[p], $10 and $12 is price per pound and $70 is total price, so that's why its = to 70)

a + p = 6.3 (this is total almonds and pistachios adding up to 6.3 pounds)

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3 years ago

Find the volume of a cylinder with a diameter of 8 inches and a height that is 3 times the radius. Use 3.14 for pi round answer

masha68 [24]

Answer:

603.19

Step-by-step explanation:

v=π $r^{2} h$

pi is 3.14

Radius= Diameter/2= 4, so r square= 16

Height= Radius*3=12

So volume= 3.14*16*12=603.19

6 0

3 years ago

I have two congruent sides. I also have two congruent angles that measure 45 degree each. I am a

Snowcat [4.5K]

45 Degrees on each side means it is equal, for an "equilateral" triangle.

4 0

3 years ago

HELP PLZZ will give brainliest <3

melisa1 [442]

Answer:

Step-by-step explanation:

First question:

You are given a side, a, and its opposite angle, A. You are also given side b. Use that in the law of sines and solve for the other angle, B.

$\dfrac{a}{\sin A} = \dfrac{b}{\sin B}$

$\dfrac{10}{\sin 30^\circ} = \dfrac{40}{\sin B}$

$\dfrac{1}{0.5} = \dfrac{4}{\sin B}$

$\sin B = 2$

The sine function can never equal 2, so there is no triangle in this case.

Answer: no triangle

Second question:

You are given a side, b, and its opposite angle, B. You are also given side c. Use that in the law of sines and solve for the other angle, C.

$\dfrac{b}{\sin B} = \dfrac{c}{\sin C}$

$\dfrac{10}{\sin 63^\circ} = \dfrac{}{\sin C}$

$\sin C = \dfrac{8.9\sin 63^\circ}{10}$

$C = \sin^{-1} \dfrac{8.9\sin 63^\circ}{10}$

$C \approx 52.5^\circ$

One triangle exists for sure. Now we see if there is a second one.

Now we look at the supplement of angle C.

m<C = 52.5°

supplement of angle C: m<C' = 180° - 52.5° = 127.5°

We add the measures of angles B and the supplement of angle C:

m<B + m<C' = 63° + 127.5° = 190.5°

Since the sum of the measures of these two angles is already more than 180°, the supplement of angle C cannot be an angle of the triangle.

Answer: one triangle

3 0

3 years ago

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finlep [7]

It would be A=18 because of the equation a^2+b^2=c^2.

3 0

3 years ago