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3 years ago

Help, please:( safasvasfas

Mathematics

1 answer:

Viefleur [7K]3 years ago

5 0

Ratios are not my thing sorry

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AnnZ [28]

Answer:

cool question I love it

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3 years ago

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Leon learned a total of 24 starter recipes over the course of 12 weeks of culinary school. After how many weeks of culinary scho

Neporo4naja [7]

Answer:

Step-by-step explanation:

He learns 2 recipes a week. So divide 30 by 2 & get 15

4 0

3 years ago

Pls help me its really late

BigorU [14]

The answer is 11/16 the probability will be very high

6 0

3 years ago

A book has 200 pages. The number of mistakes on each page is a Poisson random variable with mean 0.01, and is independent of the

aleksandr82 [10.1K]

Answer:

198 pages have no mistakes.

Step-by-step explanation:

We are given the following in the question:

The number of mistakes on a page follows a poison distribution with

$\mu = \lambda = 0.01$

Formula:

$P(X =k) = \displaystyle\frac{\lambda^k e^{-\lambda}}{k!}\\\\ \lambda \text{ is the mean of the distribution}$

We have to find the probability that there are no mistakes on a page.

$P(X =0) = \displaystyle\frac{(0.01)a^0 e^{-0.01}}{0!} = 0.9901$

Thus, approximately 99.01% of the pages have no mistakes.

Number of pages =

$\text{Total number of pages}\times 99.01\%\\\\200\times \dfrac{99.01}{100}\\\\\approx 198$

Thus, 198 pages have no mistakes.

5 0

4 years ago

Given: ΔACM, m∠C = 90º

Virty [35]

Answer:

CM=20 and CP=12

Step-by-step explanation:

The given triangle ΔACM has the measurements as follows:

m∠C=90°, CP⊥AM, AC=15, AP=9, PM=16.

To Find: CP and CM

We can use Pythagoras theorem to calculate the sides CP and CM.

Pythagoras theorem gives a relation between hypotenuse, base and height/perpendicular of a right angled triangle which is as follows:

$h^{2}=p^{2}+b^{2}$

where h is hypotenuse of triangle, b is base and p is perpendicular of triangle.

The figure shows that in ΔACM is a right angled triangle at C where,

AM --> hypotenuse

CM --> base

AC --> height

So substituting values into formula:

$AM^{2}=AC^{2}+CM^{2}$

$25^{2}=15^{2}+CM^{2}$

$625-225=CM^{2}$

$400=CM^{2}$

$\sqrt{400} =CM$

$CM=20$ , which is required answer.

Similarly, we can see that triangle ΔCPM is also a right angled triangle at P and thus Pythagoras theorem can again be applied to calculate CP. Since CM is the side opposite to right angle P, it is the hypotenuse.

So we have,

$CM^{2}=PM^{2}+CP^{2}$

$20^{2}=16^{2}+CP^{2}$

$400-256=CP^{2}$

$144=CP^{2}$

$\sqrt{144} =CP$

$CP=12$ , which is required answer.

7 0

3 years ago