On comparing values , we see that student which has the largest percent error is <u>A. Student 4: 9.61 m/s2
.</u>
<u>Explanation:</u>
Here, we have Four students measured the acceleration of gravity. The accepted value for their location is 9.78m/s2. Let's calculate which student’s measurement has the largest percent error :
<u>A. Student 4: 9.61 m/s2
</u>
Percentage of error = %.
<u>B. Student 3: 9.88 m/s2
</u>
Percentage of error = %.
<u>C. Student 2: 9.79 m/s2
</u>
Percentage of error = % .
<u>D. Student 1: 9.78 m/s2</u>
Percentage of error = % .
On comparing values , we see that student which has the largest percent error is <u>A. Student 4: 9.61 m/s2
.</u>
Answer:
Acceleration a =-1.75 m/s²
Explanation:
Given:
Initial speed u = 24 m/s
Final speed v = 10 m/s
Time taken t = 8 sec
Find:
Acceleration a
Computation:
a = (v-u)/t
a = (10-24)/8
a = -14 / 8
Acceleration a =-1.75 m/s²
Answer:
This is an example of Inelastic colission
Explanation:
Step one:
given:
mass of moose m1 = 620 kg
mass of train m2= 10,000kg
Initial velocity of moose u1= 0 m/s
Initial velocity of train v1 = 10m/s
combined velocity of the system is given as v
Applying the conservation of momentum equation we have
m1u1+ m2u1= (m1+m2)V
substitutting we have
620*0+10000*10= (620+10000)V
100000= 10620V
divide both sides by 10620
V = 100000/10620
V=9.41m/s
The velocity of the moose after impact is 9.41m/s
Answer:
Explanation:
I = Current = 500 kA
L = Length of wire = 180 m
m = Mass of train =
g = Acceleration due to gravity =
B = Magnetic field
The gravitational force and magnetic force will balance each other
The magnitude of the magnetic field needed to levitate the train is
C. Acceleration is the rate of change of velocity. So at the top of the path, while the velocity is zero, the CONSTANT GRAVITATIONAL ACCELERATION is about 10 m/s^2 (9.8)