1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Alexeev081 [22]
3 years ago
10

Imagine holding a basketball in both hands, throwing it straight up as high as you can, and then catching it when it falls. At w

hich points in time does a zero net force act on the ball? ignore air resistance
A. When you hold the ball still in your hands after catching it
B. Just after the ball first leaves your hands.
C. At the instant the ball reaches its highest point.
D. At the instant the falling ball hits your hands.
E. When you hold the ball still in your hands before it is thrown.
Physics
1 answer:
Alisiya [41]3 years ago
4 0

Answer:

C. At the instant the ball reaches its highest point.

Explanation:

When a body is thrown up, it tends to come down due to the influence of gravitational force acting on the body. The body will be momentarily at rest at its maximum point before falling. At this maximum point, the velocity of the body is zero and since force acting on a body is product of the mass and its acceleration, the force acting on the body at that point will be "zero"

Remember, F = ma = m(v/t)

Since v = 0 at maximum height

F = m(0/t)

F = 0N

This shows that the force acting on the body is zero at the maximum height.

You might be interested in
một vật được ném từ đỉnh toàn nhà cao 20m so với mặt đát với vận tốc ban đàu 12m/s hợp với phương ngang một góc 30 độ. tính khoả
Helga [31]

Sorry don't know which language is this can't understand O_o

5 0
3 years ago
2 equal charges, 27 micro Coulomb each, are separated by 5 cm. Find force between those.
padilas [110]

Answer:

The force between charges is  F= 2.624*10^3N.

Explanation:

The Coulomb force F between the two charges q_1 and q_2 separated by distance d is given by the equation

F = k\dfrac{q_1q_2}{d^2}

where k is the coulombs constant, and has the value

k= 9*10^9N\cdot C\cdot m^2.

Now in our case

q_1=q_2=27\mu C =27*10^{-6}C

and

d= 5cm =0.05m,

therefore, the Coulomb force between the charges is

F =( 9*10^9N\cdot C\cdot m^2)*\dfrac{(27*10^{-6}C)(27*10^{-6}C)}{(0.05m)^2}

\boxed{ F= 2.624*10^3N}

3 0
3 years ago
spectroscope or a spectrometer is an instrument which is used for separating the components of light, which have different wavel
ohaa [14]

Answer:

The answer is B

Explanation:

The line spectrum shows distinct light different energies and wavelengths

7 0
3 years ago
Read 2 more answers
On the way to school, Jed traveled 100m north, 300m east, 100 north, 100m east, and 100m north. A.) Find the total distance trav
Oduvanchick [21]

Answer:

Total distance = 700 m

Displacement = 500 m

Explanation:

Notice that Jed travelled a total of 3 x 100 m = 300 m in the North direction, and 300 m + 100 m = 400 m in the East direction. Therefore the total distance he travelled is:  300 + 400 = 700 m.

But the actual displacement is given by the Pythagorean theorem as the hypotenuse of a right angle triangle of legs 300 m and 400 m:

displacement = \sqrt{300^2+400^2} =\sqrt{250000} =500\,m

5 0
3 years ago
In February 1955, a paratrooper fell 370 m from an airplane without being able to open his chute but happened to land in snow, s
nevsk [136]

a) 0.94 m

The work done by the snow to decelerate the paratrooper is equal to the change in kinetic energy of the man:

W=\Delta K\\-F d = \frac{1}{2}mv^2 - \frac{1}{2}mu^2

where:

F=1.1 \cdot 10^5 N is the force applied by the snow

d is the displacement of the man in the snow, so it is the depth of the snow that stopped him

m = 68 kg is the man's mass

v = 0 is the final speed of the man

u = 55 m/s is the initial speed of the man (when it touches the ground)

and where the negative sign in the work is due to the fact that the force exerted by the snow on the man (upward) is opposite to the displacement of the man (downward)

Solving the equation for d, we find:

d=\frac{1}{2F}mu^2 = \frac{(68 kg)(55 m/s)^2}{2(1.1\cdot 10^5 N)}=0.94 m

b) -3740 kg m/s

The magnitude of the impulse exerted by the snow on the man is equal to the variation of momentum of the man:

I=\Delta p = m \Delta v

where

m = 68 kg is the mass of the man

\Delta v = 0-55 m/s = -55 m/s is the change in velocity of the man

Substituting,

I=(68 kg)(-55 m/s)=-3740 kg m/s

7 0
3 years ago
Other questions:
  • Luc, who is 1.80 m tall and weighs 950 N, is standing at the center of a playground merry-go-round with his arms extended,
    14·1 answer
  • What is the acceleration of a 25 kg mass pushed by a 10n force
    15·2 answers
  • Is it possible for speed to be constant while acceleration is not zero?
    15·1 answer
  • A book weighing 2.0 Newtons is lifted 3.0 meters in 4.0 seconds. How much work was done? SHOW WORK
    10·1 answer
  • A system of satellites, base stations, and receivers is called ___________.
    10·1 answer
  • A city bus travels six blocks east and eight blocks north east wok is 100 m long is a bus travels as distance and 15 minutes wha
    6·1 answer
  • Dos cargas de 1 pC estan a 1mm, la fuerza de interaccion entre dichas cargas es?​
    15·1 answer
  • Larger animals have sturdier bones than smaller animals. A mouse's skeleton is only a few percent of its body weight, compared t
    12·1 answer
  • Can someone help me
    7·1 answer
  • What are the three elements that magnets are made of?
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!