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Alexeev081 [22]
3 years ago
10

Imagine holding a basketball in both hands, throwing it straight up as high as you can, and then catching it when it falls. At w

hich points in time does a zero net force act on the ball? ignore air resistance
A. When you hold the ball still in your hands after catching it
B. Just after the ball first leaves your hands.
C. At the instant the ball reaches its highest point.
D. At the instant the falling ball hits your hands.
E. When you hold the ball still in your hands before it is thrown.
Physics
1 answer:
Alisiya [41]3 years ago
4 0

Answer:

C. At the instant the ball reaches its highest point.

Explanation:

When a body is thrown up, it tends to come down due to the influence of gravitational force acting on the body. The body will be momentarily at rest at its maximum point before falling. At this maximum point, the velocity of the body is zero and since force acting on a body is product of the mass and its acceleration, the force acting on the body at that point will be "zero"

Remember, F = ma = m(v/t)

Since v = 0 at maximum height

F = m(0/t)

F = 0N

This shows that the force acting on the body is zero at the maximum height.

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As shown in the figure, the ideal mechanical advantage is calculated by dividing the radius of the wheel by the radius of the axle. Any crank-operated device is an example of a wheel and axle. Force applied to a wheel exerts a force on its axle.
3 0
3 years ago
Is the rate at which velocity change?<br>____________​
krek1111 [17]

Answer:

<h2>Acceleration: </h2>

The rate of change of velocity is acceleration. Like velocity, acceleration is a vector and has both magnitude and direction. For example, a car in straight-line motion is said to have forward (positive) acceleration if it is speeding up and rearward (negative) acceleration if it is slowing down.

Explanation:

Hope it is helpful....

5 0
3 years ago
Consider two conducting spheres with one having a larger radius than the other. Both spheres carry the same amount of excess cha
RSB [31]

Answer: Option (a) is the correct answer.

Explanation:

It is known that potential energy is the energy occupied by an object or substance due to its position is known as potential energy.

Therefore, more is the space occupied by an object more will be its position at a particular location. Hence, more will be its potential energy. On the other hand, smaller is the space occupied by an object, smaller will be the position holded by it.

Hence, smaller will be its potential energy.

Thus, we can conclude that for the given situation the statement, potential energy of the larger sphere is greater than that of the smaller sphere, is true.

6 0
4 years ago
A nonuniform electric field is given by the expression vector e = ay i + bz j + cx k, where a, b, and c are constants. determine
miskamm [114]
The flux through a surface is given by the scalar product of the field strength and the area of the surface. 

As the rectangular surface is in xy plane the flux corresponding to x and y component of field will be zero (parallel to the surface) and the flux through the surface is only due to z component of the field. 
Because flux is the dot product of Electric field and area vector. So, parallel to surface is 0.
So,
The z component of the field is varying with x only and directly proportional to x coordinate. (cx k)

Consider an infinitely thin strip of the surface at a distance x from y axis of thickness dx as in figure. Field at this strip will have magnitude c*x and will be normal to the surface hence the flux through this strip will be given by :





6 0
4 years ago
Calculate the momentum of a 1,500 kg car traveling at 6 m/s.
Nonamiya [84]

Answer:

See the answers below.

Explanation:

Momentum is defined as the product of mass by velocity, in this way we have the following equation.

P=m*v

where:

P = momemtum [kg*m/s]

m = mass = 1500 [kg]

v = velocity = 6 [m/s]

P = 1500*6\\P=9000 [kg*m/s]

Now we have to calculate the momentum of the plane when it travels at 30 [m/s].

P_{airplane}=m_{plane}*v_{plane}\\P_{airplane}=7800*30\\P_{airplane}=234000[kg*m/s]

Now this same momentum must be conserved, in such a way that the mass is increased but the velocity must decrease for the momentum to be conserved.

P=m_{new}*v_{new}\\234000=(7800+800)*v_{new}\\234000=8600*v_{new}\\v_{new}=27.2[m/s]

7 0
3 years ago
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