As shown in the figure, the ideal mechanical advantage is calculated by dividing the radius of the wheel by the radius of the axle. Any crank-operated device is an example of a wheel and axle. Force applied to a wheel exerts a force on its axle.
Answer:
<h2>Acceleration: </h2>
The rate of change of velocity is acceleration. Like velocity, acceleration is a vector and has both magnitude and direction. For example, a car in straight-line motion is said to have forward (positive) acceleration if it is speeding up and rearward (negative) acceleration if it is slowing down.
Explanation:
Hope it is helpful....
Answer: Option (a) is the correct answer.
Explanation:
It is known that potential energy is the energy occupied by an object or substance due to its position is known as potential energy.
Therefore, more is the space occupied by an object more will be its position at a particular location. Hence, more will be its potential energy. On the other hand, smaller is the space occupied by an object, smaller will be the position holded by it.
Hence, smaller will be its potential energy.
Thus, we can conclude that for the given situation the statement, potential energy of the larger sphere is greater than that of the smaller sphere, is true.
The flux through a surface is given by the scalar product of the field strength and the area
of the surface.
As the rectangular surface is in xy plane the flux corresponding to x and y component of
field will be zero (parallel to the surface) and the flux through the surface is only due to z
component of the field.
Because flux is the dot product of Electric field and area vector. So, parallel to surface is 0.
So,
The z component of the field is varying with x only and directly
proportional to x coordinate. (cx k)
Consider an infinitely thin strip of the surface at a distance x from y axis of thickness dx as
in figure. Field at this strip will have magnitude c*x and will be normal to the surface hence
the flux through this strip will be given by :
Answer:
See the answers below.
Explanation:
Momentum is defined as the product of mass by velocity, in this way we have the following equation.

where:
P = momemtum [kg*m/s]
m = mass = 1500 [kg]
v = velocity = 6 [m/s]
![P = 1500*6\\P=9000 [kg*m/s]](https://tex.z-dn.net/?f=P%20%3D%201500%2A6%5C%5CP%3D9000%20%5Bkg%2Am%2Fs%5D)
Now we have to calculate the momentum of the plane when it travels at 30 [m/s].
![P_{airplane}=m_{plane}*v_{plane}\\P_{airplane}=7800*30\\P_{airplane}=234000[kg*m/s]](https://tex.z-dn.net/?f=P_%7Bairplane%7D%3Dm_%7Bplane%7D%2Av_%7Bplane%7D%5C%5CP_%7Bairplane%7D%3D7800%2A30%5C%5CP_%7Bairplane%7D%3D234000%5Bkg%2Am%2Fs%5D)
Now this same momentum must be conserved, in such a way that the mass is increased but the velocity must decrease for the momentum to be conserved.
![P=m_{new}*v_{new}\\234000=(7800+800)*v_{new}\\234000=8600*v_{new}\\v_{new}=27.2[m/s]](https://tex.z-dn.net/?f=P%3Dm_%7Bnew%7D%2Av_%7Bnew%7D%5C%5C234000%3D%287800%2B800%29%2Av_%7Bnew%7D%5C%5C234000%3D8600%2Av_%7Bnew%7D%5C%5Cv_%7Bnew%7D%3D27.2%5Bm%2Fs%5D)