Answer:
The acceleration experienced by the occupants of the spaceship during launch is 282652.782 meters per square second.
Explanation:
Let suppose that spaceship is accelerated uniformly. A yard equals 0.914 meters. A feet equals 0.304 meters. If air viscosity and friction can be neglected, then acceleration (
), measured in meters per square second, is estimated by this kinematic formula:
(1)
Where:
- Travelled distance, measured in meters.
,
- Initial and final speeds of the spaceship, measured in meters.
If we know that
,
and
, then the acceleration experimented by the spaceship is:


The acceleration experienced by the occupants of the spaceship during launch is 282652.782 meters per square second.
The mass m of the object = 5.25 kg
<h3>Further explanation</h3>
Given
k = spring constant = 3.5 N/cm
Δx= 30 cm - 15 cm = 15 cm
Required
the mass m
Solution
F=m.g
Hooke's Law
F = k.Δx

Bending occurs when one side of the wave enters the new medium before the other side of the wave. ... The bending occurs because the two sides of the wave are traveling at different speeds.