ATP ( adenosine triphosphate )
Answer:
The number of photons per second that strike the given area is 2.668 x 10⁸ photons/second
Explanation:
Given;
intensity of the sunlight, I = 2.00 kJ·s−1·m^−2
area of incident, A = 5.2 cm² = 5.2 x 10⁻⁴ m²
Energy of incident photons per second on the given area;
E = IA
E = (2000)( 5.2 x 10⁻⁴)
E = 1.04 J/s
Energy of a photon is given is by;
The number of photons per second that strike the given area is;
Therefore, the number of photons per second that strike the given area is 2.668 x 10⁸ photons/second
The question is incomplete. The mass of the object is 10 gram and travelling at a speed of 2 m/s.
Solution:
It is given that mass of object before explosion is,m = 10 g
Speed of object before explosion, v = 2 m/s
Let be the masses of the three fragments.
Let be the velocities of the three fragments.
Therefore, according to the law of conservation of momentum,
So the x- component of the velocity of the m2 fragment after the explosion is,
∴
The last one (words that have the same sound but different spellings and meanings)
Answer:
1. Magnetic force = 4.56*10^-12 N
2. Acceleration = 5.01 *10^18 m/s^2
3. A) The direction of the moving electron will change but its speed will remain constant.
Explanation:
Given Data:
B = 0.0040 T North
q = 1.6*10^-19 C
Mass of electron = 9.1*10^-31 kg
V = 9.5% of speed of light
= 9.5% *3*10^8
= 28.5*10^6 m/s west
So, B and v are perpendicular to each other.
Therefore, ∅ = 90°
1, Calculating the magnetic force using the formula;
F = qvBsin∅
= 1.6*10^-19 * 28.5*10^6*sin90
= 4.56*10^-12 N
Therefore, the strength of the force = 4.56*10^-12 N
2. Calculating acceleration using the formula;
F = ma
a = F/m
= 4.56*10^-12 /9.1*10^-31
= 5.01 *10^18 m/s^2
3. A) The direction of the moving electron will change but its speed will remain constant.