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victus00 [196]
3 years ago
10

Leaves uses_,_and_to make food for the plant​

Physics
2 answers:
Evgen [1.6K]3 years ago
5 0
Light water and carbon dioxide
LenaWriter [7]3 years ago
4 0

light, water, carbon dioxide

Explanation:

c02 , h20 and light

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What is the mass of a cart that accelerates at 3.0 m/s if a 0.5 N force is applied?
frozen [14]

The mass of the cart is 0.167 kg

Explanation:

We can solve the problem by using Newton's second law, which states that the net force applied to an object is equal to the product between its mass and its acceleration:

F=ma

where

F is the net force acting on an object

m is its mass

a is its acceleration

For the cart in this problem, we have

F = 0.5 N is the net force applied

a=3.0 m/s^2 is the acceleration

Substituting, we find the mass:

m=\frac{F}{a}=\frac{0.5}{3.0}=0.167 kg

Learn more about Newton's second law:

brainly.com/question/3820012

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#LearnwithBrainly

6 0
3 years ago
In his novel From the Earth to the Moon (1866), Jules Verne describes a spaceship that is blasted out of 12,000 yards/s. the Col
saw5 [17]

Answer:

The acceleration experienced by the occupants of the spaceship during launch is 282652.782 meters per square second.

Explanation:

Let suppose that spaceship is accelerated uniformly. A yard equals 0.914 meters. A feet equals 0.304 meters. If air viscosity and friction can be neglected, then acceleration (a), measured in meters per square second, is estimated by this kinematic formula:

a = \frac{v^{2}-v_{o}^{2}}{2\cdot \Delta s } (1)

Where:

\Delta s - Travelled distance, measured in meters.

v_{o}, v - Initial and final speeds of the spaceship, measured in meters.

If we know that v_{o} = 0\,\frac{m}{s}, v = 10968\,\frac{m}{s} and \Delta s = 212.8\,m, then the acceleration experimented by the spaceship is:

a = \frac{\left(10968\,\frac{m}{s} \right)^{2}-\left(0\,\frac{m}{s} \right)^{2}}{2\cdot (212.8\,m)}

a = 282652.782\,\frac{m}{s^{2}}

The acceleration experienced by the occupants of the spaceship during launch is 282652.782 meters per square second.

5 0
3 years ago
An ideal spring with spring constant k is hung from the ceiling. The initial length of the spring, with nothing attached to the
hram777 [196]

The mass m of the object = 5.25 kg

<h3>Further explanation</h3>

Given

k = spring constant = 3.5 N/cm

Δx= 30 cm - 15 cm = 15 cm

Required

the mass m

Solution

F=m.g

Hooke's Law

F = k.Δx

\tt m.g=k.\Delta x\\\\m.10=3.5\times 15\\\\m=5.25~kg

7 0
3 years ago
A 2500-ohm is connected to a 110v power supply. What is the current through the resistor
Assoli18 [71]

Answer:

0.044 amps

Explanation:

Givens

R = 2500 ohms

E = 110 volts

I = ?

Equation

I = E/R

Solution

I = 110/2500

I = 0.044 amps

7 0
3 years ago
All waves change speed when they enter a new medium, but they don't always bend. When does bending occur?
Anastaziya [24]
Bending occurs when one side of the wave enters the new medium before the other side of the wave. ... The bending occurs because the two sides of the wave are traveling at different speeds.
5 0
3 years ago
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