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Nina [5.8K]
3 years ago
5

The area of a parallelogram is 64 m2. If a diagonal divides the parallelogram into 2 triangles, what is the area of 1 of the tri

angles?
a. 4 m2
b. 128 m2
c. 32 m2
d. 8 m2
Mathematics
1 answer:
maw [93]3 years ago
3 0

Answer:

32\:\mathrm{m^2}

Step-by-step explanation:

When cut by a diagonal, the parallelogram will be divided into two congruent triangles. By definition, congruent polygons have equal areas. Therefore, let the area of each of the triangle be x:

x+x=64,\\2x=64,\\x=\frac{64}{2}=\boxed{32\:\mathrm{m^2}}

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Find the value of x
nataly862011 [7]

Answer:

x = 128°

Step-by-step explanation:

123 + 109 + x = 360

x = 360 - (123 + 109)

x = 360 - 232

x = 128°

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3 years ago
Suppose that v is an eigenvector of matrix A with eigenvalue λA, and it is also an eigenvector of matrix B with eigenvalue λB. (
galben [10]

Answer:

(a) Yes, λ_{A}+λ_{B}

(b) Yes, λ_{A}λ_{B}

Step-by-step explanation:

First, lets understand what are eigenvectors and eigenvalues?

Note: I am using the notation λ_{A} to denote Lambda(A) sign.

v is an eigenvector of matrix A with eigenvalue λ_{A}

v is also eigenvector of matrix B with eigenvalue λ_{B}

So we can write this in equation form as

Av=λ_{A}v

So what does this equation say?

When you multiply any vector by A they do change their direction. any vector  that is in the same direction as of Av, then this v  is called the eigenvector of A. Av is λ_{A} times the original v. The number λ_{A} is the eigenvalue of A.

λ_{A} this number is very important and tells us what is happening when we multiply Av. Is it shrinking or expanding or reversed or something else?

It tells us everything we need to know!

Bonus:

By the way you can find out the eigenvalue of Av by using the following equation:

det(A-λI)=0

where I is identity matrix of the size of same as A.

Now lets come to the solution!

(a) Show that v is an eigenvector of A + B and find its associated eigenvalue.

The eigenvalues of A and B are λ_{A} and λ_{B}, then

(A+B)(v)=Av+Bv=(λ_{A})v + (λ_{B})v=(λ_{A}+λ_{B})(v)

so,  (A+B)(v)=(λ_{A}+λ_{B})(v)

which means that v is also an eigenvector of A+B and the associated eigenvalues are λ_{A}+λ_{B}

(b) Show that v is an eigenvector of AB and find its associated eigenvalue.

The eigenvalues of A and B are λ_{A} and λ_{B}, then

(AB)(v)=A(Bv)=A(λ_{B})=λ_{B}(Av)=λ_{B}λ_{A}(v)=λ_{A}λ_{B}(v)

so,  

(AB)(v)=λ_{A}λ_{B}(v)

which means that v is also an eigenvector of AB and the associated eigenvalues are λ_{A}λ_{B}

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3 years ago
Suppose that 11 inches of wire costs 44cents.
maksim [4K]
6 inches of wire can be bought with 24 cents.

44/11 = 4
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3 years ago
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Place the quadratic y=2x^2+24x+79 into vertex form by using the method of completing the square and then state the coordinates o
katrin2010 [14]

Answer:

y=2(x+6)^2+7

(-6,7)

Step-by-step explanation:

y=2x^2+24x+79

Completing the square is a process of converting a quadratic equation in standard form into vertex form.

The first step in completing the square is grouping the quadratic and linear terms of the quadratic equation.

y=(2x^2+24x)+79

Factor out the coefficient of the quadratic term,

y=2(x^2+12x)+79

Now complete the square, add a term to make the grouped part of the equation a complete square, then balance the equation.

y=2(x^2+12x+36-36)+79

Simplify,

y=2(x^2+12x+36)+79+(2)(-36)

y=2(x+6)^2+79-72

y=2(x+6)^2+7

The x-coordinate of the vertex of the equation is equal to (-1) times the numerical part of the quadratic term, and the y-coordinate is equal to the constant.

(-6,7)

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kirill [66]
The simplified answer is 4/5
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