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Dmitry_Shevchenko [17]
3 years ago
10

Which equation in parallel to 3x-5y=10

Mathematics
1 answer:
Vaselesa [24]3 years ago
3 0

3x-5y=n

3x-5y=1

----------------------------

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Solve by using elimtation
Wewaii [24]

Answer:

1. x = 5, y = 13/2

2. x = 15 , y = 24

Step-by-step explanation:

Solve the following system:

{8 y + 6 x = 82 | (equation 1)

{6 y + 9 x = 84 | (equation 2)

Swap equation 1 with equation 2:

{9 x + 6 y = 84 | (equation 1)

{6 x + 8 y = 82 | (equation 2)

Subtract 2/3 × (equation 1) from equation 2:

{9 x + 6 y = 84 | (equation 1)

{0 x + 4 y = 26 | (equation 2)

Divide equation 1 by 3:

{3 x + 2 y = 28 | (equation 1)

{0 x + 4 y = 26 | (equation 2)

Divide equation 2 by 2:

{3 x + 2 y = 28 | (equation 1)

{0 x + 2 y = 13 | (equation 2)

Divide equation 2 by 2:

{3 x + 2 y = 28 | (equation 1)

{0 x + y = 13/2 | (equation 2)

Subtract 2 × (equation 2) from equation 1:

{3 x + 0 y = 15 | (equation 1)

{0 x + y = 13/2 | (equation 2)

Divide equation 1 by 3:

{x + 0 y = 5 | (equation 1)

{0 x + y = 13/2 | (equation 2)

Collect results:

Answer: {x = 5, y = 13/2

_____________________________________

Solve the following system:

{8 y + 3 x = 237 | (equation 1)

{3 y + 5 x = 147 | (equation 2)

Swap equation 1 with equation 2:

{5 x + 3 y = 147 | (equation 1)

{3 x + 8 y = 237 | (equation 2)

Subtract 3/5 × (equation 1) from equation 2:

{5 x + 3 y = 147 | (equation 1)

{0 x + (31 y)/5 = 744/5 | (equation 2)

Multiply equation 2 by 5/31:

{5 x + 3 y = 147 | (equation 1)

{0 x + y = 24 | (equation 2)

Subtract 3 × (equation 2) from equation 1:

{5 x + 0 y = 75 | (equation 1)

{0 x + y = 24 | (equation 2)

Divide equation 1 by 5:

{x + 0 y = 15 | (equation 1)

{0 x + y = 24 | (equation 2)

Collect results:

Answer: {x = 15 , y = 24

3 0
2 years ago
For what values of 0 is sin 0< cos0 when 0_<0< pie
8090 [49]

Answer:

vvnbn bnjmb h bm mb jhk j

Step-by-step explanation:

tunfghcbvhcbdthndfbgb

6 0
3 years ago
What is 0.275 0.20 0.572 and 0.725 greatest to least
Andru [333]
.725 , .572 , .275, .2
You look at the first decimal place to see which is the greatest. 7 is greater than 5 and 2 so it's first. Then 5 is greater than 2 so it is next. For the last two numbers since 2 is the same value you look at the next decimal place. Since 7 is greater than 0 it comes next!
6 0
3 years ago
The Midpoint of AB dkdldl
Nutka1998 [239]
  • The Midpoint of AB is (1,0).

Given that:

  • In line AB, where the coordinates of A is (3,1) and coordinates of B is (-1,-1).

To find:

  • The Midpoint of line AB.

So, according the question

We know that,

The midpoint M of a line segment AB with endpoints A (x₁, y₁) and B (x₂, y₂) has the coordinates M ( \frac{x_1 + x_2}{2} , \frac{y_1 + y_2}{2} ).

Now from question,

We know that the the coordinates of A is (3,1) and coordinates of B is (-1,-1) of line AB.

So, we can say that

   A is (3,1) or x₁ = 3 and y₁ = 1.

   B (-1,-1) or x₂ = -1 and y₂ = -1.

∵ The coordinates of midpoint M (X,Y)

          X = \frac{x_1 + x_2}{2}

              = \frac{3-1}{2}

              = 2/2

          X = 1.

And

          Y = \frac{y_1 + y_2}{2}

              = \frac{1-1}{2}

              = 0/2

          Y = 0.

So, the midpoint of line AB is M (1,0)

To learn more about Midpoint of line, please click on the link;

brainly.com/question/14687140

#SPJ1

8 0
1 year ago
If angle 1 is 140°, then find the measure of the other angles.
Vlad [161]
<h2><u>Angles</u></h2>

<h3>If angle 1 is 140°, then find the measure of the other angles.</h3>

  • ∠2 = <u>40°</u>
  • ∠3 = <u>40°</u>
  • ∠4 = <u>140°</u>
  • ∠5 = <u>140°</u>
  • ∠6 = <u>40°</u>
  • ∠7 = <u>40°</u>
  • ∠8 = <u>140°</u>

<u>Explanation:</u>

  • The relationship between ∠1 and ∠2 are <u>supplementary angles</u>, so when you <u>add up their measurements, it will become 180°</u>. Simply subtract 180 and 140 to get the measure of ∠2. As well as ∠3, they're <u>linear pairs</u>. And they are also <u>supplementary</u>. To determine the measure of ∠6 and ∠7, notice the <u>relationship</u> between ∠2 and ∠6. As you noticed, it is <u>corresponding angles</u>. So they <u>have the same measurement</u>. If <u>∠2 = 40°</u>, then <u>∠6 = 40°</u>. As well as ∠7, because the relationship between ∠6 and ∠7 are <u>vertical pairs</u>. So the angle measurement of ∠7 is also <u>40°</u>.

  • Meanwhile, the relationship between ∠1 and ∠4 are <u>vertical pairs</u>. It means they also <u>have the same measurement</u>. So ∠4 = <u>140°</u>. The relationship between ∠1 and ∠5 are <u>corresponding angles</u>, so they also <u>have the same measurement</u>. If <u>∠1 = 140°</u>, then <u>∠5 = 140°</u>. The relationship between ∠1 and ∠8 are <u>alternate exterior angles</u>, and they also <u>have the same measurement</u>. <u>If ∠1 = 140°</u>, then <u>∠8 = 140°</u>.

Wxndy~~

8 0
2 years ago
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