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Fittoniya [83]
3 years ago
13

NO SILLY ANSWER, OR JUST DOING IT FOR THE POINTS!! WILL GIVE BRAINLEYEST

Mathematics
2 answers:
Paha777 [63]3 years ago
7 0
Answer:
9a/ -3a
Explanation:
FrozenT [24]3 years ago
4 0

Answer:

9a/ -3a

Step-by-step explanation:

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Find the equation of the line that passes through the given points. (1, 4.5) and (3, 6)
Zanzabum

Answer:

y=0.75x+3.75

Step-by-step explanation:

The slope is

\frac{6 - 4.5}{3 - 1}  =   \frac{3}{4}

Substituting into point-slope form,

y - 6 = 0.75(x - 3)

y - 6 = 0.75x - 2.25

y = 0.75x + 3.75

6 0
2 years ago
I need help with something. Can you solve this: 15% of 48.
Hitman42 [59]
The answer would be 7.2
7 0
4 years ago
Read 2 more answers
kelly plans to put her graduation money into an account and leave it there for 4 years while she goes to collge she recieves $75
DedPeter [7]

Answer:

FV=887.3967212 $

Step-by-step explanation:

Use the compound-interest formula:

FV=PV(1+\frac{r}{n}) ^{nt}

Where:

FV=Future value or the ending amount

PV=Present value or the initial amount=750

n=Number of compoundings in any one year=2

t=Total number of years=4

r=interest rate=0.0425

Now, replacing the data in the equation:

FV=750*(1+\frac{0.0425}{2}) ^{2*4} =887.3967212 $

4 0
3 years ago
4. Meagan invests $1,200 each year in an IRA for 12 years in an account that earned 5%
Nina [5.8K]
Part A)

\bf \qquad \qquad \textit{Future Value of an ordinary annuity}\\
\left. \qquad \qquad \right.(\textit{payments at the end of the period})
\\\\
A=pymnt\left[ \cfrac{\left( 1+\frac{r}{n} \right)^{nt}-1}{\frac{r}{n}} \right]

\bf \qquad 
\begin{cases}
A=
\begin{array}{llll}
\textit{accumulated amount}\\
\end{array}
\begin{array}{llll}

\end{array}\\
pymnt=\textit{periodic payments}\to &1200\\
r=rate\to 5\%\to \frac{5}{100}\to &0.05\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{annually, thus once}
\end{array}\to &1\\
t=years\to &12
\end{cases}

\bf A=1200\left[ \cfrac{\left( 1+\frac{0.05}{1} \right)^{1\cdot  12}-1}{\frac{0.05}{1}} \right]\implies A\approx 19100.55

part B)

so, for the next 11 years, she didn't make any deposits on it and simple let it sit and collect interest, compounded annually at 5%.

\bf \qquad \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\  
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$19100.55\\
r=rate\to 5\%\to \frac{5}{100}\to &0.05\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{annually, thus once}
\end{array}\to &1\\
t=years\to &11
\end{cases}
\\\\\\
A=19100.55\left(1+\frac{0.05}{1}\right)^{1\cdot  11}\implies A\approx 32668.42

part C)

well, for 12 years she deposited 1200 bucks, that means 12 * 1200, or 14,400.

now, here she is, 12+11, or 23 years later, and she's got 32,668.42 bucks?

all that came out of her pocket was 14,400, so 32,668.42 - 14,400, is how much she earned in interest.
6 0
4 years ago
The temperature on a winter night was -23 degrees. The temperature rose by 5 degrees when the sun came up. When he sun set again
dexar [7]
-23+5-7=-25...................
4 0
4 years ago
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