9-(.5)^(4)/48
= 9-0.0013020833
=8.9986
1. arc to pqr
adc to psr
rcd to qrs
rad to qps
2.ar to pq
rc to qr
CD to RS
ad to ps
3. 1.5
4 sp
5rsp
Answer:
Part 1) The area of the structure is 
Part 2) The slab will contain
of cement
Step-by-step explanation:
Part 1) Find the area of the structure
we know that
The area of the structure is equal to the area of rectangle plus the area of semicircle
<u><em>Find the area of rectangle</em></u>
The area of rectangle is equal to

we have


substitute


<u><em>Find the area of semicircle</em></u>
The area of semicircle is

we have


substitute


<u><em>Find the area of the structure</em></u>
Adds the areas

Part 2) If the structure is 6 in thick, how many cubic feet of cement will the slab contain?
Remember that

Convert inches to feet

<u><em>Find the volume of the structure</em></u>
To obtain the volume , multiply the area by 0.5 ft (thick)
so

Y2-y1/x2-x1
7-(-2)/-3-6= 9/-9= -1
slope= -1