Answer:
The runner with a mean running time of 6.2
Step-by-step explanation:
The value range parameters of the three runners are;
The mean running time of the runner, A = 6.2
The mean running time of the runner, B = 7.4
The mean running time of the runner, C = 6.9
The interquartile range of the runner, A = 1.1
The interquartile range of the runner, B = 0.02
The interquartile range of the runner, C = 0.08
Whereby the number of running times for the 3 runners is large, and with the assumption that distribution of the mean is normal, we have
The mean = The mode of the data
Therefore, the minimum, and maximum running time of the runners are;
Runner A;
Minimum running time = 6.2 - 1.1 = 5.1
Maximum running time = 6.2 + 1.1 = 7.3
Runner B;
Minimum running time = 7.4 - 0.02 = 7.38
Maximum running time = 7.4 + 0.02 = 7.42
Runner C;
Minimum running time = 6.9 - 0.08 = 6.82
Maximum running time = 6.9 + 0.08 = 6.98
The fastest runner has the lowest running time;
Therefore, the fastest runner is runner A with a mean running time of 6.2 with a minimum running time of 5.1
