Question

A farmer sells 8.7 kilograms of apples and pears at the farmer's market. 3/5 of this weight is apples, and the rest is pears. How many kilograms of pears did she sell at the farmer's market?

Answer 1

Answer:

$8.7 = \frac{3}{5}*8.7 + P$

Where P represent the kilograms of pears for this case and if we solve for P we got:

$P = 8.7 - \frac{3}{5} *8.7 = 8.7 (1- \frac{3}{5})= 8.7 *\frac{2}{5} = 3.48 Kg$

And we can check that the total sum is 8.7:

$5.22 +3.48 = 8.7$

So then the final answer would be 3.48 Kg of pears

Step-by-step explanation:

For this case we know that the total amount sold was 8.7 Kg. And we know in addition that 3/5 of this weight is from apples. So then the rest $1- \frac{3}{5} = \frac{2}{5}$ correspong to pears.

We can set up the following equation:

$8.7 = \frac{3}{5}*8.7 + P$

Where P represent the kilograms of pears for this case and if we solve for P we got:

$P = 8.7 - \frac{3}{5} *8.7 = 8.7 (1- \frac{3}{5})= 8.7 *\frac{2}{5} = 3.48 Kg$

And we can check that the total sum is 8.7:

$5.22 +3.48 = 8.7$

So then the final answer would be 3.48 Kg of pears