The rms potential difference is defined as the peak value of the potential difference divided by the square root of 2:
where
is the peak value of the voltage (the maximum voltage).
The generator in our problem has a maximum voltage of
, so its rms potential difference is
Yes but it gets a little more complicated unfortunately. The kinematic equations work more easily when you calculate the average acceleration. If that is not possible, you will need to separate the the work into parts where the acceleration is constant. IF you have a problem where the change in acceleration is exponential you would need an integral calculation.
<em>HOWEVER</em>, Even if you are under the impression that acceleration is changing in some non-linear fashion, you are probably over thinking it a bit. Simply calculate the <em>average</em> acceleration and work with that.
If you think about it, acelleration is just an expression of the <em>rate of change</em> of velocity. If that rate of change is its self changing, then that just equates to a different rate of change in velocity, i.e a different acceleration (or average acceleration). SO just take the 'average' acceleration, knowing that there is no such thing physically.
Answer:
v = 17.9 m/s
Explanation:
As we know that the normal force measured by the sensor before the ride is started is given as
now when the rider has reached at the top position of the loop then the normal force is given as
now at the top position we have
so we have
Find out what the force is and yiy have your answer
Answer:
10 hours earlier than regular train
Explanation:
In this case you are already giving the expression to be used which is:
S = D/t (1)
The problem is giving us the data of the speed of both trains, and we also know the distance between City A and B, which is 4000 km, therefore, we just need to solve for t in the above expression for both trains, and then, do the difference between their times and see how much earlier the express train arrives.
Solving for t, we have:
t = D/S (2)
For Train 1 (The regular):
t₁ = 4000 / 80
t₁ = 50 h
For Train 2 (Express):
t₂ = 4000 / 100
t₂ = 40 h
Now, as expected express train arrives earlier, now let's see how much:
T = t₁ - t₂
T = 50 - 40
<h2>
T = 10 h</h2><h2>
</h2>
Therefore, Express train arrives 10 hours earlier than regular train.
Hope this helps