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nikitadnepr [17]
3 years ago
15

A generator's maximum output is 220 V. What is the rms potential difference?

Physics
1 answer:
seraphim [82]3 years ago
3 0
The rms potential difference is defined as the peak value of the potential difference divided by the square root of 2:
V_{rms} =  \frac{V_0}{ \sqrt{2} }
where
V_0 is the peak value of the voltage (the maximum voltage).

The generator in our problem has a maximum voltage of V_0=220 V, so its rms potential difference is
V_{rms}= \frac{V_0}{ \sqrt{2} }=155.6 V
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\int\limits^s_0 {a} \, ds  = \int\limits^v_0 {v} \, dv\\ \int\limits^s_0 {6+0.02s} \, ds  = \int\limits^v_0 {v} \, dv\\ 6s + \frac{0.02s^{2} }{2} = \frac{1}{2} v^{2} \\v = \sqrt{12s + 0.02s^{2} } .....................1 \\\\\\

Remember that

v = \frac{ds}{dt} \\\frac{ds}{v} = dt\\\int\limits^s_0 {\frac{ds}{\sqrt{12s+0.02s^{2} } } } \, ds = \int\limits^t_0 {} \, dt \\t=  (5\sqrt{2} ) ln  \frac{| [s + 300 + \sqrt{(s^{2}  + 600s)} ] |}{300} .......2

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Two particles each of mass m and charge q are suspended by strings of length / from a common point. Find the angle e that each s
ozzi

Answer:

\theta =\left (\frac{kq^{2}}{4L^{2}\times mg}  \right )^{\frac{1}{3}}

Explanation:

Let the length of the string is L.

Let T be the tension in the string.

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Divide equation (1) by equation (2), we get

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As θ is very small, so tanθ and Sinθ is equal to θ.

\theta ^{3} =\frac{kq^{2}}{4L^{2}\times mg}

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