Answer:
∆p=(m2v)kg.m/s
Explanation:
∆p=mv where v=2v. hence ∆p=m2v
<u>Answer:</u> The correct answer is Option 3.
<u>Explanation:</u>
Amplitude of as sound wave is defined as the extent to which the air particles are getting displaced.
Speed of the sound wave is defined as the distance traveled by the sound wave per unit time and is not related to the amplitude of a sound wave.
Wavelength of the sound wave is defined as the difference between two crests or troughs.
Loudness of a sound wave is defined as the size of the vibration which are produced by it. This is closely related to the amplitude of the sound wave.
Pitch is defined as the sensation of the frequency. Higher the frequency, the pitch is also high and vice-versa.
From the above information, the amplitude of a sound wave is most closely related to the sound’s loudness.
Hence, the correct answer is Option 3.
Answer:
The correct answer is:
(a) 0
(b) 0.5 m/s
(c) 7740 N
(d) 0
Explanation:
The given values are:
mass,
m = 3000 kg
Tension,
T = 7,200 N
Angle,
= 30°
(a)
Even as the block speed becomes unchanged, the kinetic energy (KE) will adjust as well:
⇒
By using the theorem of energy, the net work done will be:
⇒
(b)
According to the question, After 0.25 m the block is moving with the constant speed
= 0.5 m/s.
(c)
The given kinetic friction coefficient is:
u = 0.3
The friction force will be:
=
On substituting the values, we get,
=
=
=
=
(d)
On including the friction,
The net work will be:
⇒
Answer:
F(t) = (-6.00 N/s^2)t^2
a(t) = (-3.00 N/s^2)t^2
Because F = ma, the acceleration function is the force function divided by mass (3.50 kg). Because the force is acting to the left, a negative has been introduced.
Take the integral of the acceleration function with the power rule for integrals. Initial velocity is 8.00 m/s
∫a(t) dt=v(t)+v1
v(t)=(-1m/s^4)*t^3+9 m/s
Setting velocity equal to zero and solving for t.
v(t)=0
t^3=9s^3
t=∛9s
=2.08 s
The integral of velocity is position. The object begins at the origin so initial position is 0
∫v(t) dt= x(t)
x(t)=(-0.25m/s^4)*t^4+(9m/s)*t
Plugging the t from step 3 into the x(t) function from step 4. This is the answer to part a.
x(2.08)=14 m
plug 3.50 s into the velocity function from step 2. Speed is the absolute value of velocity. This is the answer to part b.
v(3.5)=(1 m/s^4)(3.5 s)^3+9 m/s
= -18 m/s
speed(3.5 s)=║v(3.5)║=18 m/s