Mass does not affect the pendulum's swing. The longer the length of string, the farther the pendulum falls; and therefore, the longer the period, or back and forth swing of the pendulum. The greater the amplitude, or angle, the farther the pendulum falls; and therefore, the longer the period.
Answer:
C
Explanation:
got a one hundred on the test
Idk its really weird because the ridges are making the quarter stand and therefore able to roll
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Answer:
, the minus meaning west.
Explanation:
We know that linear momentum must be conserved, so it will be the same before (
) and after (
) the explosion. We will take the east direction as positive.
Before the explosion we have
.
After the explosion we have pieces 1 and 2, so
.
These equations must be vectorial but since we look at the instants before and after the explosions and the bomb fragments in only 2 pieces the problem can be simplified in one dimension with direction east-west.
Since we know momentum must be conserved we have:
![Mv_i=m_1v_1+m_2v_2](https://tex.z-dn.net/?f=Mv_i%3Dm_1v_1%2Bm_2v_2)
Which means (since we want
and
):
![v_2=\frac{Mv_i-m_1v_1}{m_2}=\frac{Mv_i-m_1v_1}{M-m_1}](https://tex.z-dn.net/?f=v_2%3D%5Cfrac%7BMv_i-m_1v_1%7D%7Bm_2%7D%3D%5Cfrac%7BMv_i-m_1v_1%7D%7BM-m_1%7D)
So for our values we have:
![v_2=\frac{(145kg)(24m/s)-(115kg)(65m/s)}{(145kg-115kg)}=-133.17m/s](https://tex.z-dn.net/?f=v_2%3D%5Cfrac%7B%28145kg%29%2824m%2Fs%29-%28115kg%29%2865m%2Fs%29%7D%7B%28145kg-115kg%29%7D%3D-133.17m%2Fs)