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kirill [66]
3 years ago
14

The main difference between speed and velocity involves

Physics
2 answers:
ad-work [718]3 years ago
7 0
D. Direction, if someone is traveling on an interstate from New York to Boston at 65 MPH, the speed of the car is 65 MPH and the velocity is 65 MPH north-east.
inn [45]3 years ago
3 0
Speed does not include direction.
Velocity includes direction. 

Therefore, the main difference between speed and velocity is D. Direction.

FINAL ANSWER: D. direction
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If a reaction occurs when a piece of metal is placed in a solution, what can you conclude about the solution?
Tju [1.3M]
You can conclude that the solution is probably acidic because bases rarely react with metals.
5 0
3 years ago
What is the hottest layer in the Sun's atmosphere?
erica [24]
I believe it is the core
7 0
2 years ago
A student does 686 J of work on an object in 3.1 seconds. What is the power output of the student?
Alenkinab [10]

Answer:

221.29 Watts

Explanation:

P=W/t

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P=221.29 Watts

5 0
2 years ago
.<br> Why are objects that fall near Earth's surface rarely in free fall?
gtnhenbr [62]

Answer:

Objects that fall near Earth’s surface are rarely in free fall.

"Free fall" is the situation where the ONLY force on an object is

the force of gravity, and nothing else.

Objects near Earth's surface are almost always surrounded by air.

If they are falling, then the air is exerting forces on them, and they

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Explanation:

8 0
3 years ago
Read 2 more answers
A typical 100-watt light bulb consumes 100 j of energy per second. If a light bulb converts all of this energy to 400 nm light
VladimirAG [237]

The missing question is: how many photons are produced per second?

Answer:

2.0\cdot 10^{20}

Explanation:

The energy of a photon is given by

E_1 = \frac{hc}{\lambda}

where

h is the Planck constant

c is the speed of light

\lambda is the wavelength of the photon

In this problem, the photons have wavelength

\lambda = 400 nm = 400 \cdot 10^{-9} m, so each photon has an energy of

E_1 = \frac{(6.63\cdot 10^{-34})(3\cdot 10^8)}{400\cdot 10^{-9}}=4.97\cdot 10^{-19} J

The total energy emitted by the bulb in 1 second is

E = 100 J

Therefore, the number of photons emitted per second is

n=\frac{E}{E_1}=\frac{100}{4.97\cdot 10^{-19}}=2.0\cdot 10^{20}

3 0
3 years ago
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