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Nina [5.8K]
2 years ago
8

Which of the following pollutants are most likely the result of a malfunctioning chimney?

Advanced Placement (AP)
2 answers:
Illusion [34]2 years ago
8 0

Answer:

Particulate Matter

Explanation:

Carbon monoxide occurs when there is not enough oxygen

nitrogen oxide occurs in an internal combustion engine with the pressure

particulate matter would increase with a poor chimney

III only

possibly CO

ch4aika [34]2 years ago
4 0

Answer: it’s all three of them.

Explanation: this is for sure the answer as I just took the quiz and got it wrong when I put only carbon monoxide.

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Which of the following identifies an error in Mathus' theory?
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D.- Food production grew much more quickly than Malthus predicted
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Hello, I need help with a calculus FRQ. My teacher has given a hint that this last part has to do with the intermediate value th
lesya [120]

Answer:

Yes, at a time t such that (√2)/2 ≤ t ≤ 2.

Explanation:

To answer the question

Therefore, where the domain of the function is the set of all real numbers x for which f(x) is a real number we have

For Chloe's velocity

C(t) = t\times e^{4-t^2} \ for \ 0\leq t\leq 2

Finding the boundaries of the function gives;

0\times e^{4-0^2} = 0 and 2\times e^{4-2^2} = 2

At t = 1, we have 1\times e^{4-1^2} = e^{3} = 20.086

We find the maximum point as follows;

\frac{\mathrm{d} \left (t\times e^{4-t^2}   \right )}{\mathrm{d} x}=0

From which we have;

\frac{\mathrm{} e^{4-t^2} - t\times e^{4-t^2} \times2\times t }{(e^{4-t^2} )^2}=0

e^{4-t^2} - t\times e^{4-t^2} \times2\times t }=0

e^{4-t^2}(1 - t\times2\times t })=0\\e^{4-t^2}(1 - 2\times t^2 })=0\\

e^{4-t^2}=0 or (1 - 2\times t^2 })=0

∴ 1 = 2·t² and from which t = (√2)/2

Hence the function C(x) is decreasing from t = (√2)/2 to t = 2

For Brandon

For 0 ≤ t ≤ 1, 1 ≤ B(t) ≤8 and for 1 < t ≤ 2, 8 < B(t) ≤ 1.5

1 ≤ f(x) ≤ 1.5

Given that the function B(t) is differentiable, therefore, continuous, there exists a point at which the function C(t) and B(t) intersects given that;

For 0 ≤ t ≤ (√2)/2, 0 ≤ C(t) ≤ 23.416 for (√2)/2 < t ≤ 2, 23.416 > C(t) ≥ 2

and for  0 ≤ t ≤ 0  1 ≤ B(t) ≤ 8 and for 1 < t ≤ 2, 8 > B(t) ≥ 1.5

Therefore, the curves intersect at in between (√2)/2 ≤ t ≤ 2.

8 0
3 years ago
Explanations
podryga [215]

The sampling distribution of the sample means for the random sample of 100 dogs will be 0.25.

<h3>How to compute the sample mean?</h3>

From the given information, the population distribution of the QDA scores for the fur of dogs is roughly uniform with mean 5.4 and standard deviation is 2.5.

In this case, the sampling distribution of the sample means will be:

= ✓SD/n

= ✓(2.5)²/100

= ✓0.0625

= 0.25

In conclusion, the correct option is 0.25.

Learn more about sampling on:

brainly.com/question/24466382

3 0
2 years ago
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