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3 years ago

How to solve this problem

Mathematics

1 answer:

RSB [31]3 years ago

5 0

Holy @$#% THAT LOOKS HARD! Sorry, I can't help I don't know that math yet.

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Please help me i’m being timed

Vera_Pavlovna [14]

Answer:

...............c

Step-by-step explanation:

6 0

3 years ago

Y = 6x − 4

Kamila [148]

Answer:

Part B: $\displaystyle [1, 2]$

Part A: Set both equation equal to each other by Substitution, since our y-values are already given to us.

Step-by-step explanation:

6x - 4 = 5x - 3

- 6x + 3 - 6x + 3

____________

$\displaystyle -1 = -x; 1 = x$

Plug this coordinate back into the above equations to get the y-coordinate of 2.

y = mx + b [where b is the y-intercept and the rate of change (slope) is represented by m]

$\displaystyle y = 5x - 3; [0, -3]; 5 = m \\ y = 6x - 4; [0, -4]; 6 = m$

I am joyous to assist you at any time.

3 0

3 years ago

Type the equivalent fraction using the multiplier 2. 4/5

natulia [17]

8/10 is an equivalent fraction for 4/5.

7 0

3 years ago

Mark all true statements. Group of answer choices

laiz [17]

Answer:

True

False

Step-by-step explanation:

a) The first statement is the basis for Euclid's algorithm to compute the gcd of two nonnegative integers a,b. You can prove this as follows.

Let G=gcd(a,b). Since r=a-bq and G divides a and G divides b, then G divides r. Now, G divides a and G divides r, hence G divides gcd(b,r).

On the other hand, since a=bq+r, and gcd(b,r) divides b and r, then gcd(b,r) divides a. Therefore gcd(b,r) divides a and b, which implies that gcd(b,r) divides G.

x divides y and y divides x implies that |x|=|y|. The GCD's are nonnegative, therefore G=gcd(b,r).

b) It is false. In general, to test for primality of N, you have to check that all primes smaller than N do not divide N. In this case, we have to check for 2,3,5,7,11,13,17,19,23,...

101 is prime, but this may be false in general. For example, consider N=13*11=143. N is not prime, and n is not divisible by 2,3,5, or 7.

5 0

3 years ago

I need help plz.......................................

umka21 [38]

Which one do you need help with

4 0

3 years ago