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3 years ago

Solve 1/3x - 5/6x =1/4

Mathematics

1 answer:

Harrizon [31]3 years ago

8 0

Answer:

-1/2

Step-by-step explanation:

Given:

$\frac{1}{3}x - \frac{5}{6} x = \frac{1}{4}$

Find the common denominator for the fractions, which is 6. Rewrite 1/3 as 2/6.

$\frac{2}{6}x - \frac{5}{6} x = \frac{1}{4}$

Combine like terms.

$-\frac{3}{6} x = \frac{1}{4}$

Simplify.

-0.5x = 1/4

Divide both sides by -0.5.

x = -1/2 = -0.5

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3 years ago

One zero of f(x)=x^3-2x^2-5x+6 is 1 what are other zeros of the function

elena-s [515]

Answer:

The other zeros are -2 and 3.

Step-by-step explanation:

As 1 is a zero then (x - 1) is a factor so we divide:

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3 years ago

Read 2 more answers

A circle has a radius of 6 centimeters and a circumference of 12π centimeters. The radius of the circle is then multiplied by 5.

artcher [175]

Answer:

The answer is 60

Step-by-step explanation:

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3 years ago

Given segments AB and CD intersect at E.

nata0808 [166]

The length of a segment is the distance between its endpoints.

$\mathbf{AB = 3\sqrt{2}}$
AB and CD are not congruent
AB does not bisect CD
CD does not bisect AB

(a) Length of AB

We have:

$\mathbf{A = (1,2)}$

$\mathbf{B = (4,5)}$

The length of AB is calculated using the following distance formula

$\mathbf{AB = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}}$

So, we have:

$\mathbf{AB = \sqrt{(1 - 4)^2 + (2 - 5)^2}}$

$\mathbf{AB = \sqrt{18}}$

Simplify

$\mathbf{AB = 3\sqrt{2}}$

(b) Are AB and CD congruent

First, we calculate the length of CD using:

$\mathbf{CD = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}}$

Where:

$\mathbf{C = (2, 4)}$

$\mathbf{D = (2, 1)}$

So, we have:

$\mathbf{CD = \sqrt{(2 -2)^2 + (4 - 1)^2}}$

$\mathbf{CD = \sqrt{9}}$

$\mathbf{CD = 3}$

By comparison

$\mathbf{CD \ne AB}$

Hence, AB and CD are not congruent

(c) AB bisects CD or not?

If AB bisects CD, then:

$\mathbf{AB = \frac 12 \times CD}$

The above equation is not true, because:

$\mathbf{3\sqrt 2 \ne \frac 12 \times 3}$

Hence, AB does not bisect CD

(d) CD bisects AB or not?

If CD bisects AB, then:

$\mathbf{CD = \frac 12 \times AB}$

The above equation is not true, because:

$\mathbf{3 \ne \frac 12 \times 3\sqrt 2}$

Hence, CD does not bisect AB

Read more about lengths and bisections at:

brainly.com/question/20837270

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