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svp [43]
3 years ago
8

If A={1,2,3,4,5},AUB={3,4,5}and sub={1,2,3,4,5,6},find the set B​

Mathematics
1 answer:
mars1129 [50]3 years ago
6 0

Answer:

1 +2+3+4+5

aub 314+5

sub 1-2-3-4_5_6

1234567

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Multiply and subtract
WITCHER [35]

Answer:

26x³ - 12x² + 5x + 7

Step-by-step explanation:

  1. (2x³ - 3x + 11) - (3x² + 1) x (4 - 8x)
  2. 2x³ - 3x+11 - (12x² - 24x³ + 4 - 8x)
  3. 2x³ - 3x + 11 - 12x² + 24x³ - 4 + 8x
  4. 26x³ + 5x + 7 - 12x²

= 26x³ - 12x² + 5x + 7

4 0
3 years ago
Which of the following examples has a unit rate of 50 miles per hour? Select all that apply.
Usimov [2.4K]

Answer:

I believe your answer would be the following:

A) 250 miles in 5 hours.

C) 200 miles in 4 hours

E) 700 miles in 14 hour

Step-by-step explanation:

Unit rate = 50

A) 250 miles in 5 hours // 50*5 = 250 (CORRECT)

B) 300 miles in 5 hours // 50*5 ≠ 300 (WRONG)

C) 200 miles in 4 hours // 50*4 = 200 (CORRECT)

D) 240 miles in 4 hours // 50*4 ≠ 240 (WRONG)

E) 700 miles in 14 hours // 50*14 = 700 (CORRECT)

Hope this helps! :)

8 0
3 years ago
Read 2 more answers
A parallelogram has sides 20cm and 30cm with an angle of 80 between the two sides. What is the length of each of the diagonals?
Lelu [443]

Answer:

length of diagonals are BD = 33.039 cm and AC = 38.84 cm

Step-by-step explanation:

given,

sides of parallelogram is 20 cm and 30 cm

Angle between them is 80°. opposite angle of parallelogram are same the opposite angle is same.

other angle  = 360° - 80° - 80° + 2 x = 200

                                        x = 100°

Using cosine law

c² = a² + b² - 2ab cos γ

In ΔDAB

BD² = 30² + 20 ² - 2 × 30 × 20 cos 80°

BD = 33.039 cm

now in ΔADC

c² = a² + b² - 2ab cos γ

AC² = 20² + 30² - 2 × 30 × 20 cos 100°

AC = 38.84 cm

length of diagonals are BD = 33.039 cm and AC = 38.84 cm

6 0
3 years ago
-9a + 11ad - 35a + ad
34kurt
-9a + 11ad - 35a + ad = -44a + 12ad

hope this helps
4 0
3 years ago
Read 2 more answers
Find an identity for cos(4t) in terms of cos(t)
mestny [16]
So you can do this multiple ways, I'll do this the way that I think makes sense the l most easily.

Cos (0) = 1
Cos (pi/2)=0
Cos (pi) =-1
Cos (3pi/2)=0
Cos (2pi)=1

Now if you multiply the inside by 4, the graph oscillates more violently (goes up and down more in a shorter period).
But you can always reduce it.
Cos (0)= 1
Cos (4pi/2) = cos (2pi)=1
Cos (4pi) =Cos (2pi) =1 (Any multiple of 2pi ==1)
etc...
the pattern is that every half pi increase is now a full period as apposed to just a quarter of one. That's in theory.

Now that you know that, the identities of Cosine are another beast, but mathematically.
You have.

Cos (2×2t) = Cos^2 (2t)-Sin^2 (2t)
Sin^2 (t)=-Cos^2 (t)+1..... (all A^2+B^2=C^2)
Cos (2×2t) = Cos^2 (t)-(-Cos^2 (t)+1)
Cos (2×2t)= 2Cos^2 (2t) - 1

2Cos^2 (2t) -1= 2 (Cos^2(t)-Sin^2(t))^2 -1
(same thing as above but done twice because it's cos ^2 now)
convert sin^2
2Cos^2 (2t)-1 =2 (Cos^2 (t)+Cos^2 (t)-1)^2 -1
2 (2Cos^2(t)-1)^2 -1
2 (2Cos^2 (t)-1)(2Cos^2 (t)-1)-1
2 (4Cos^4 (t) - 2 (2Cos^2 (t))+1)-1
Distribute

8Cos^4 (t) -8Cos^2 (t) +1

Cos (4t) =8Cos^4-8Cos^2 (t)+-1






5 0
3 years ago
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