Answer:
the speed of the bullet before striking the block is 302.3 m/s.
Explanation:
Given;
mass of the bullet, m₁ = 28.3 g = 0.0283 kg
mass of the wooden block, m₂ = 5004 g = 5.004 kg
initial velocity of the block, u₂ = 0
final velocity of the bullet-wood system, v = 1.7 m/s
let the initial velocity of the bullet before striking the block = u₁
Apply the principle of conservation of linear momentum to determine the initial velocity of the bullet.
m₁u₁ + m₂u₂ = v(m₁ + m₂)
0.0283u₁ + 5.004 x 0 = 1.7(0.0283 + 5.004)
0.0283u₁ = 8.5549
u₁ = 8.5549 / 0.0283
u₁ = 302.3 m/s
Therefore, the speed of the bullet before striking the block is 302.3 m/s.
Answer:
The spotted owl is an example of an indicator species, or an organism that shows the overall health of an environment. This could be an animal, like the owl, a bacterium, a plant, a fish, well you get the idea.
Let the initial velocity of the car be u.
Final velocity of the car (v) = 5.43 m/s
deceleration (a) = - 2.78 m/s^2
Time taken (t) = 2.26 s
Using the first equation of motion:
v = u + at
u = v - at
u = 5.43 + 6.28
u = 11.71 m/s
Let the car's displacement be x.
Using second equation of motion:
x = 26.4646 - 7.0995
x = 19.3651 meters
Hence, the displacement of the car is 19.36 meters
The answer is <span>atmospheric layer</span>
