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Juliette [100K]
3 years ago
12

A milliliter of very hot water is added to a liter of very cold water. Which of these events will occur? Assume the surrounding

air is at room temperature.
a. The cold water will warm to room temperature.
b. The hot water will cool down.
c. The cold water will warm up.
d. The cold water will warm up, but will never reach room temperature.
Physics
2 answers:
Nadya [2.5K]3 years ago
7 0
Answer shall be B.the hot water will cool down.
prisoha [69]3 years ago
5 0

Answer:b

Explanation:the water will not be hot nomore because of the cold water

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A force of 3600 N is exerted on a piston that has an area of 0.030 m2. What force is exerted on a second piston that has an area
Airida [17]
For Pascal's law, the pressure is transmitted with equal intensity to every part of the fluid:
p_1 = p_2
which becomes
\frac{F_1}{A_1}= \frac{F_2}{A_2}
where
F_1=3600 N is the force on the first piston
A_1=0.030 m^2 is the area of the first piston
F_2 is the force on the second piston
A_2=0.015 m^2 is the area of the second piston

If we rearrange the equation and we use these data, we can find the intensity of the force on the second piston:
F_2=F_1  \frac{A_2}{A_1}=(3600 N) \frac{0.015 m^2}{0.030 m^2}= 1800 N
7 0
3 years ago
Read 2 more answers
A 99.1-kg baseball player slides into second base. The coefficient of kinetic friction between the player and the ground is μk =
Stels [109]

Answer:

628.022466 N

8.61 m/s

Explanation:

m = Mass

\mu = Coefficient of friction

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration

g = Acceleration due to gravity = 9.81 m/s²

F_f=\mu mg\\\Rightarrow F_f=0.646\times 99.1\times 9.81\\\Rightarrow F_f=628.022466\ N

Magnitude of frictional force is 628.022466 N

F=ma\\\Rightarrow a=\frac{F_f}{m}\\\Rightarrow a=\frac{628.022466}{99.1}\\\Rightarrow a=6.33726\ m/s^2

v=u+at\\\Rightarrow 0=u-6.33726\times 1.36\\\Rightarrow u=8.61\ m/s

Initial speed of the player is 8.61 m/s

4 0
3 years ago
Caleb is filling up water balloons for the Physics Olympics balloon tosscompetition. Caleb sets a 0.50-kg spherical water balloo
Mashcka [7]

a)

• P = F/A

P = pressure = 630 N/m^2

F = force

A = area

F = mg = 0.50 kg x 9.8 m/s^2 = 4.9 N

m= mass

g= gravity

P = F/A

A = F/P

A = 4.9 N / 630 N/m^2 = 7.778 x 10^-3 m^2

b)

• Area of a circle = pi* radius ^2

7.778 x 10^-3 m^2 = pi* radius ^2

√(7.778 x 10^-3 m^2 / pi ) = radius

radius = 0.04976 m

Answers:

a ) 7.778 x 10^-3 m^2

b) 0.04976 m

8 0
1 year ago
Atom: Finally, there is the ever-so-tiny atom. It takes extremely powerful microscopes to view
katovenus [111]
A

That should be correct!!!
6 0
3 years ago
Physics HELP!
shusha [124]

Answer:

1. B

2. A

Explanation:

1. The displacement is the change in position.  At t = 0, x = 1.0.  At t = 8.0, x = 6.0.  So from t=0 to t=8, Δx = 6.0 − 1.0 = 5.0.

2. The instantaneous velocity is the slope of the tangent line at any point of a position vs. time graph.

The average velocity is the displacement divided by the time interval.

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3 years ago
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