For Pascal's law, the pressure is transmitted with equal intensity to every part of the fluid:
which becomes
where
is the force on the first piston
is the area of the first piston
is the force on the second piston
is the area of the second piston
If we rearrange the equation and we use these data, we can find the intensity of the force on the second piston:
Answer:
628.022466 N
8.61 m/s
Explanation:
m = Mass
= Coefficient of friction
t = Time taken
u = Initial velocity
v = Final velocity
s = Displacement
a = Acceleration
g = Acceleration due to gravity = 9.81 m/s²
Magnitude of frictional force is 628.022466 N
Initial speed of the player is 8.61 m/s
a)
• P = F/A
P = pressure = 630 N/m^2
F = force
A = area
F = mg = 0.50 kg x 9.8 m/s^2 = 4.9 N
m= mass
g= gravity
P = F/A
A = F/P
A = 4.9 N / 630 N/m^2 = 7.778 x 10^-3 m^2
b)
• Area of a circle = pi* radius ^2
7.778 x 10^-3 m^2 = pi* radius ^2
√(7.778 x 10^-3 m^2 / pi ) = radius
radius = 0.04976 m
Answers:
a ) 7.778 x 10^-3 m^2
b) 0.04976 m
Answer:
1. B
2. A
Explanation:
1. The displacement is the change in position. At t = 0, x = 1.0. At t = 8.0, x = 6.0. So from t=0 to t=8, Δx = 6.0 − 1.0 = 5.0.
2. The instantaneous velocity is the slope of the tangent line at any point of a position vs. time graph.
The average velocity is the displacement divided by the time interval.
