Explanation:
The scanner records the time from when a ultrasound wave is emitted to when its reflection is received. A technician calculates the depth of the reflection using the equation as :
The distance covered by ultrasonic wave when it was emitted and gets reflected is 2d. Speed is given by :
d is distance and t is time
Here, d = 2d
So, the factor of (1/2) is used because the distance covered by the wave is 2 times when it was emitted and received.
Answer:
Product,
P = 639619.091888
Explanation:
In this case, we need to find the product of two numbers. These are as follows :
On doing calculation, we get the product of two numbers as :
P = 639619.091888
In scientific notation the product of two number is given by :
Hence, this is the required solution.
Answer:
The energy that the truck lose to air resistance per hour is 87.47MJ
Explanation:
To solve this exercise it is necessary to compile the concepts of kinetic energy because of the drag force given in aerodynamic bodies. According to the theory we know that the drag force is defined by
Our values are:
Replacing,
We need calculate now the energy lost through a time T, then,
But we know that d is equal to
Where
v is the velocity and t the time. However the time is given in seconds but for this problem we need the time in hours, so,
(per hour)
Therefore the energy that the truck lose to air resistance per hour is 87.47MJ