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swat32
2 years ago
13

sheldon bought 4 1/2 kg of plant food. he uses 1 2/3 kg on his strawberry plant and used 1/4 kg for his tomato plant. how many k

g of plant food did sheldon have left
Mathematics
1 answer:
fenix001 [56]2 years ago
4 0

Answer:

Sheldon have left 2\frac{7}{12}\ kg of food.

Step-by-step explanation:

Quantity of food = 4\frac{1}{2}=\frac{9}{2} kg

Quantity used on strawberry plant = 1\frac{2}{3} = \frac{5}{3}\ kg

Quantity used on tomato plant = \frac{1}{4}\ kg

Food left = Total - used on strawberry - used on tomato

Food left = \frac{9}{2}-\frac{5}{3}-\frac{1}{4}

Food left = \frac{54-20-3}{12} = \frac{31}{12}

Food left = 2\frac{7}{12}\ kg

Therefore,

Sheldon have left 2\frac{7}{12}\ kg of food.

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Answer:

tan(2u)=[4sqrt(21)]/[17]

Step-by-step explanation:

Let u=arcsin(0.4)

tan(2u)=sin(2u)/cos(2u)

tan(2u)=[2sin(u)cos(u)]/[cos^2(u)-sin^2(u)]

If u=arcsin(0.4), then sin(u)=0.4

By the Pythagorean Identity, cos^2(u)+sin^2(u)=1, we have cos^2(u)=1-sin^2(u)=1-(0.4)^2=1-0.16=0.84.

This also implies cos(u)=sqrt(0.84) since cosine is positive.

Plug in values:

tan(2u)=[2(0.4)(sqrt(0.84)]/[0.84-0.16]

tan(2u)=[2(0.4)(sqrt(0.84)]/[0.68]

tan(2u)=[(0.4)(sqrt(0.84)]/[0.34]

tan(2u)=[(40)(sqrt(0.84)]/[34]

tan(2u)=[(20)(sqrt(0.84)]/[17]

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0.84=0.04(21)

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3 years ago
Khan Acad
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Answer:

7.222 (repeating)

Step-by-step explanation:

8 + 10 + 8 + 5 + 4 + 7 + 5 + 10 + 8 = 65

1      2    3    4    5    6    7    8     9

65 / 9 = 7.222 (repeating)

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