Question

Can anyone please help me with this? You need to find the equation to solve for x, the value of x, and the value of each angle measure for all 5 questions. I will give brainliest

Answer 1

Answer:

$1. 3x+21 = 6x-60\\or, 6x-3x = 21+60 [Being~corresponding~angles]\\or, 3x = 81\\or, x = 27.\\Equations: 3x+21=6x-60\\Value ~of ~x = 27\\Angle ~measure = (3x+21), (6x-60) = 3(27)+21,6(27)-60 = 102,102$

$2. 12x - 18 = 8x+10 [Being~vertically~opposite~angles]\\or, 12x - 8x = 18+10\\or, 4x = 28\\or, x = 7\\Equations: 12x-18 = 8x+10\\Value~ of~ x: 7\\Angle ~measure: (12x-18),(8x+10) = 66,66$

$3. Have~a~look~at~the~figure.\\Here, y = 3x+9 [Being~ vertically ~opposite ~angles]\\Also, y+5x+3 = 180^{o} [ Being~cointerior~angles]\\or, 3x^{o}+9^{o}+5x^{o}+3^{o}=180^{o}\\or, 8x^{o}+12^{o}=180^{0}\\or, 8x^{o} = 168^{o}\\or, x = 21^{o}\\So, 3x+9 = 3(21)+0 = 72^{o} ~and ~5x+3 = 5(21)+3 = 108^{o}\\Equations: y = 3x +9, y+5x+3=180^{o}\\Value ~of~ x: 21^{o}\\Angle ~measure: 72^{o},108^{o}$

$4.~~~~ (3x+10)^{o}+(3x-28)^{o} = 180^{o} [Being~cointerior~angles]\\or, ~~~6x -18^{o} = 180^{o}\\or, 6x=198^{o}\\or, x = 33^{o}\\So, 3x+10 = 3(33)+10 = 109^{o}~and~3x-28 = 3(33)-28 = 71^{o}\\Equations: 3x+10+3x-28 = 180^o\\Value~ of~ x: 33^o\\Angle~measure: 109^o,71^o$

$5. Solution,\\12x+15 = 15x [Being ~alternate~angles]\\or, 15x-12x = 15\\or, 3x=15\\or, x = 5^{o}\\So, 12x+15 = 12(5)+15 = 75^o = 15x\\Equations: 12x+15=15x\\Value~of~x: 5^o\\Angle ~measure: 75^o,75^o$