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3 years ago

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A car travels 2 1/3 miles in 3 1/2 minutes at a constant speed. a) Write an equation to represent the distance the car travels,d

, in miles for m minutes. b) Write an equation to represent the distance the car travels,d, in miles for h hours

2 answers:

Stels [109]3 years ago

8 0

Distance + time = ( equals) speed so... Idek lol

DaniilM [7]3 years ago

7 0

You would put 2&1/3 over 2&1/3 =x or something like that

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Can y'all please help asap!

Gemiola [76]

1) 0.4

2)0.875

i dont know the 3 and 4 one

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3 years ago

Read 2 more answers

Which correlation coefficient implies that the data points are closest to the line that is used to model the

pochemuha

Answer:

r= 0.87

Step-by-step explanation:

It has the strongest correlation, which means it is closest to the line.

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4 years ago

In the previous part, we obtained dy dx = 3t2 − 27 −2t . Next, find the points where the tangent to the curve is horizontal. (En

mina [271]

Answer:

(27.55, 7.22), (-11.3, 3.21).

Step-by-step explanation:

When is the tangent to the curve horizontal?

The tangent curve is horizontal when the derivative is zero.

The derivative is:

$\frac{dy}{dx} = 3t^{2} - 2t - 27$

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

$ax^{2} + bx + c, a\neq0$ .

This polynomial has roots $x_{1}, x_{2}$ such that $ax^{2} + bx + c = a(x - x_{1})*(x - x_{2})$ , given by the following formulas:

$x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}$

$x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}$

$\bigtriangleup = b^{2} - 4ac$

In this question:

$3t^{2} - 2t - 27 = 0$

So

$a = 3, b = -2, c = -27$

Then

$\bigtriangleup = b^{2} - 4ac = (-2)^{2} - 4*3*(-27) = 328$

So

$t_{1} = \frac{-(-2) + \sqrt{328}}{2*3} = 3.35$

$t_{2} = \frac{-(-2) - \sqrt{328}}{2*3} = -2.685$

Enter your answers as a comma-separated list of ordered pairs.

We found values of t, now we have to replace in the equations for x and y.

t = 3.35

$x = t^{3} - 3t = (3.35)^{3} - 3*3.35 = 27.55$

$y = t^{2} - 4 = (3.35)^2 - 4 = 7.22$

The first point is (27.55, 7.22)

t = -2.685

$x = t^{3} - 3t = (-2.685)^3 - 3*(-2.685) = -11.3$

$y = t^{2} - 4 = (-2.685)^2 - 4 = 3.21$

The second point is (-11.3, 3.21).

8 0

3 years ago

Find the product or (x^2+4x-3)(2x^2+x+6)

Stells [14]

The answer is
3x^2+5x+3

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4 years ago

I need to earn $350,000 for a pet gorilla. In 3 days, I earn $100. How many days do I have to wait before I have $350,000

Annette [7]

1,166 days I know this because I just did the math rig now

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3 years ago