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Olin [163]
2 years ago
6

A car travels 2 1/3 miles in 3 1/2 minutes at a constant speed. a) Write an equation to represent the distance the car travels,d

, in miles for m minutes. b) Write an equation to represent the distance the car travels,d, in miles for h hours
Mathematics
2 answers:
Stels [109]2 years ago
8 0
Distance + time = ( equals) speed so... Idek lol
DaniilM [7]2 years ago
7 0
You would put 2&1/3 over 2&1/3 =x or something like that
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notka56 [123]

Answer:

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the points make a sad face on the graph  and if you do the vertical line test you can see that its a function

3 0
3 years ago
What is the annual interest rate if $1600 is invested for 6 years and $456 in interest is earned
sergij07 [2.7K]
Use the formula   i = p*r*t:
                                                               $456
$456 = $1600*r*6.  Solving for r, r = ----------------- = 0.0475, or 4 3/4%
                                                           ($1600)(6)
6 0
3 years ago
.6 is ten times as much as
Triss [41]
.6 divided by 10 is .06 so .6 is 10 times more than .06
5 0
2 years ago
Read 2 more answers
Simplify a x 3a^3b <br><br> Help me nowwwwwww
sweet-ann [11.9K]
Simplify the expression and you get 3a^4B
8 0
3 years ago
Select the two values of x that are roots of this equation.
makkiz [27]

Answer:

\implies x = (-2) \qquad or\qquad x = \dfrac{-3}{2}

Step-by-step explanation:

<u>Given </u><u>:</u><u>-</u><u> </u>

  • A quadratic equation is given to us.
  • The equation is 2x² + 7x +6=0

And we need to find out the roots of the given equation. We can use the middle term splitting method to find out the roots as ,

<u>Given </u><u>equation</u><u> </u><u>:</u><u>-</u>

\implies 2x^2 + 7x +6=0

Step 1: <u>Find</u><u> out</u><u> the</u><u> </u><u>factors</u><u> </u><u>of </u><u>1</u><u>2</u><u> </u><u>:</u><u>-</u><u> </u>

We will choose the two factors such that their sum equals to the coefficient of x i.e. 7 .The factors are , 1×12 , 2×6 , 3×4 .

  • And 3 + 4 = 7. So we will break the middle term into 3x and 4x .

Step 2 :<u> Breaking</u><u> the</u><u> </u><u>middle</u><u> term</u><u> </u><u>:</u><u>-</u><u> </u>

\implies 2x^2 + 3x+4x +6=0

Step 3: <u>Take </u><u>out </u><u>common</u><u> </u><u>from </u><u>terms </u><u>:</u><u>-</u>

\implies x(2x + 3) +2(2x +3)=0

\implies ( x +2)(2x+3)=0

Step 4 : <u>Equate </u><u>them </u><u>with </u><u>0</u><u> </u><u>:</u><u>-</u><u> </u>

\implies x = (-2) \qquad or\qquad x = \dfrac{-3}{2}

<u>Hence </u><u>the</u><u> </u><u>correct</u><u> </u><u>options </u><u>are </u><u>C </u><u>and </u><u>D </u><u>.</u>

5 0
2 years ago
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