Ask question

Ask question

All categories

3 years ago

11

Determine the mass of CO2 formed if 15 grams of C4H10

1 answer:

Svetlanka [38]3 years ago

4 0

Answer:

$m_{CO_2}=45gCO_2$

Explanation:

Hello there!

In this case, since the combustion of butane is:

$C_4H_{10}+\frac{13}{2} O_2\rightarrow 4CO_2+5H_2O$

Thus, since the molar mass of butane is 58.12 g/mol and that of carbon dioxide is 44.01 g/mol, we obtain the following mass of CO2 product:

$m_{CO_2}=15gC_4H_{10}*\frac{1molC_4H_{10}}{58.12gC_4H_{10}} *\frac{4molCO_2}{1molC_4H_{10}} *\frac{44.01gCO_2}{1molCO_2} \\\\m_{CO_2}=45gCO_2$

Best regards!

You might be interested in

2C2H6 + 8O2 = 4CO2 + 6H2O

Neporo4naja [7]

Answer:

4 moles of carbon

6 moles of water

Explanation:

I think as there no data given u have to is the numbers infront of the equation e.g 4CO2 so 4.

hope this helps :)

4 0

2 years ago

A relationship in which one variable increases as the other variable decreases is an inverse relationship.

Brut [27]

Answer:

TRUE

Explanation:

HOPE IT WILL HELP YOU

8 0

2 years ago

A gas has a volume of 1.75L at -23°C and 150.0 kPa. At what temperature would the gas occupy 1.30L at 210.0 kPa?

Nastasia [14]

Answer:

At -13 $^{0}\textrm{C}$ , the gas would occupy 1.30L at 210.0 kPa.

Explanation:

Let's assume the gas behaves ideally.

As amount of gas remains constant in both state therefore in accordance with combined gas law for an ideal gas-

$\frac{P_{1}V_{1}}{T_{1}}=\frac{P_{2}V_{2}}{T_{2}}$

where $P_{1}$ and $P_{2}$ are initial and final pressure respectively.

$V_{1}$ and $V_{2}$ are initial and final volume respectively.

$T_{1}$ and $T_{2}$ are initial and final temperature in kelvin scale respectively.

Here $P_{1}=150.0kPa$ , $V_{1}=1.75L$ , $T_{1}=(273-23)K=250K$ , $P_{2}=210.0kPa$ and $V_{2}=1.30L$

Hence $T_{2}=\frac{P_{2}V_{2}T_{1}}{P_{1}V_{1}}$

$\Rightarrow T_{2}=\frac{(210.0kPa)\times (1.30L)\times (250K)}{(150.0kPa)\times (1.75L)}$

$\Rightarrow T_{2}=260K$

$\Rightarrow T_{2}=(260-273)^{0}\textrm{C}=-13^{0}\textrm{C}$

So at -13 $^{0}\textrm{C}$ , the gas would occupy 1.30L at 210.0 kPa.

5 0

3 years ago

The elements lithium and oxygen react explosively to form lithium oxide,Li2O. how many moles of lithium oxide will form if 4.37

anygoal [31]

From the equation,

4 mole of lithium produces 2 mole of lithium oxide

4.37 mol of lithium produces (4.37÷4)x2 mol of lithium oxide

5 0

3 years ago

PLS HELP IF YOU WANT A BRAINLIEST BEST ANSWER CHOICE GETS BRAINLIEST Which describes the two cells formed through mitosis?

luda_lava [24]

Answer:C

Explanation:

did it

6 0

3 years ago