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Andreyy89
3 years ago
11

Determine the mass of CO2 formed if 15 grams of C4H10

Chemistry
1 answer:
Svetlanka [38]3 years ago
4 0

Answer:

m_{CO_2}=45gCO_2

Explanation:

Hello there!

In this case, since the combustion of butane is:

C_4H_{10}+\frac{13}{2} O_2\rightarrow 4CO_2+5H_2O

Thus, since the molar mass of butane is 58.12 g/mol and that of carbon dioxide is 44.01 g/mol, we obtain the following mass of CO2 product:

m_{CO_2}=15gC_4H_{10}*\frac{1molC_4H_{10}}{58.12gC_4H_{10}} *\frac{4molCO_2}{1molC_4H_{10}} *\frac{44.01gCO_2}{1molCO_2} \\\\m_{CO_2}=45gCO_2

Best regards!

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Explanation:

Surface tension is a force that hold the molecules in the surface to minimize the surface area.

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3 years ago
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6 0
2 years ago
2.56 g of hydrogen reacts completely with 20.32 g of oxygen<br> to form X g of water. X = g
Brilliant_brown [7]

Answer:

Mass of water produced is 22.86 g.

Explanation:

Given data:

Mass of hydrogen = 2.56 g

Mass of oxygen = 20.32 g

Mass of water = ?

Solution:

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2H₂ + O₂   →  2H₂O

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Number of moles = mass/ molar mass

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Now we will compare the moles of water with oxygen and hydrogen.

                    O₂            :            H₂O

                     1              :             2

                  0.635        ;            2×0.635 =  1.27

                   H₂             :              H₂O

                    2              :              2

                 1.28            :           1.28

The number of  moles of water produced by oxygen are less thus it will be limiting reactant.

Mass of water produced:

Mass = number of moles × molar mass

Mass = 1.27 × 18 g/mol

Mass = 22.86 g

 

4 0
4 years ago
Read 2 more answers
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olga nikolaevna [1]

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4 0
3 years ago
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KATRIN_1 [288]

Answer:

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Explanation:

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8 0
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