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Igoryamba
3 years ago
12

15.0mL of an unknown concentration of HCl reacts completely with 20.00mL of 1.0M NaOH.determine the concentration of the acid

Chemistry
1 answer:
Shtirlitz [24]3 years ago
3 0
Molar mass HCl = 36.5 g/mol  and NaOH = 40.0 g/mol

molarity of NaOH = 1.0 M

Volume of NaOH = 20.00 mL in liters : 20.00 / 1000 = 0.02 L

Number of moles NaOH :

n = M * V

n = 1.0 * 0.02

n =  0.02 moles Of NaOH

Finally Molarity of the <span>acid solution
</span>
Volume HCl :  15.0 mL in liters : 15.0 / 1000 = 0.015 L

1 HCl + 1 NaOH = 1 H₂O + 1 NaCl

1 mole HCl --------- 1 mole NaOH
? mole HCl --------- <span> 0.02 moles NaOH
</span>
moles HCl = 0.02 * 1 / 1

= 0.02 moles of HCl

M ( HCl) = n / V

= 0.02 / 0.015

= 1.333 M of HCl

hope this helps!





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Explanation:

First we <u>convert 53.768 kg into g</u>:

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Then we <u>divide the total mass of M&M's by the mass of one peanut M&M,</u> in order to calculate the answer:

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Answer:Osmotic pressure is the minimum amount of pressure a solution must exert in order to prevent from crossing a barrier by osmosis. Solute molecules have difficulty crossing semipermeable membranes, so the more solutes that are in a solution, the higher the osmotic pressure will be. Between 30% sucrose and 60% sucrose, 60% sucrose will have a greater osmotic pressure than 30% because it has a higher percentage of solutes. However, since sucrose has a higher potential to cross semipermeable membranes and is more absorbable than magnesium sulfate, magnesium sulfate would have a higher osmotic pressure than 60% sucrose even though 60% sucrose has higher molecules.

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Answer:

7.32g of HNO3 are required.

Explanation:

1st) From the balanced reaction we know that 2 moles of HNO3 react with 1 mole of Ca(OH)2 to produce 2 moles of H2O and 1 mole of Ca(NO3)2.

From this, we find that the relation between HNO3 and Ca(OH)2 is that 2 moles of HNO3 react with 1 mole of Ca(OH)2.

2nd) This is the order of the relations that we have to use in the equation to calculate the grams of nitric acid:

• starting with the 4.30 grams of Ca(OH)2.

,

• using the molar mass of Ca(OH)2 (74g/mol).

,

• relation of the 2 moles of HNO3 that react with 1 mole of Ca(OH)2 .

,

• using the molar mass of HNO3 (63.02g/mol).

4.30g\text{ Ca\lparen OH\rparen}_2*\frac{1\text{ mol Ca\lparen OH\rparen}_2}{74g\text{ Ca\lparen OH\rparen}_2}*\frac{2\text{ moles HNO}_3}{1\text{ mole Ca\lparen OH\rparen}_2}*\frac{63.02g\text{ HNO}_3}{1\text{ mole HNO}_3}=7.32g\text{ HNO}_3

So, 7.32g of HNO3 are required.

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