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matrenka [14]
3 years ago
13

What is NADPH2 ? where is it used?

Chemistry
1 answer:
uysha [10]3 years ago
3 0
<span>NADPH2 (or NADPH) - nicotinamide adenine dinucleotide phosphate</span>

NADPH2 transfers hydrogen in the process of photosynthesis
You might be interested in
true or false does the octet rule state that all atoms want to have 8 valence electrons in the outer shell
ladessa [460]

Answer:

false?

Explanation:

The octet rule refers to the tendency of atoms to prefer to have eight electrons in the valence shell. When atoms have fewer than eight electrons, they tend to react and form more stable compounds

5 0
3 years ago
What is the volume of a 200. gram sample of gold if its density is known to be 20.5 g/cm3?
Travka [436]

The volume  of  a  200 g sample  of  gold    is   9.76  cm³

<u><em> calculation</em></u>

  volume = mass /density

mass =  200 g

volume = 20.5 g/Cm³

volume  is therefore = 200g / 20.5 g/cm³  = 9.76 cm³


3 0
4 years ago
Please help I’ll brainleist you
NARA [144]

Answer:

1. They can tell that a reaction has taken place if there is formation of gas bubbles in the test tube as well as if the metal dissolves in the acid solution

2. To determine which metal is more reactive, they would compare how fast each reaction occurs. The most reactive metal would have the fastest rate of reaction with a vigorous formation of bubbles, whereas the least reactive metal will have the slowest rate of reaction.

Explanation:

1. Metal which are more electropositive than hydrogen displace hydrogen from dilute acids with the formation of the salt of the metal and evolution of hydrogen gas. Therefore, the formation of gas bubbles in the test tube indicates that a reaction is taking place.

2. The rate of formation of the gas bubbles as well as the time taken for the reaction to come to a completion by the dissolution of the metal in the acid indicates which metal is more reactive. The most reactive metal would have the fastest rate of reaction with a vigorous formation of bubbles, whereas the least reactive metal will have the slowest rate of reaction.

However, the rate of the reaction is also affected by the concentration of the acid used. The higher the concentration of the acid, the faster the reaction rate.

8 0
3 years ago
In 1983, a pilot miscalculated the fuel requirement for Air Canada Fight 143 from Montreal to Edmonton. Halfway through the flig
drek231 [11]

Answer:

27,397.23 L would be needed for a successful trip.

Explanation:

The problem gives us <u>the density (ρ) of the fuel,</u> by telling us that there are 803 g of fuel in 1 L, in which case:

ρ=\frac{mass}{Volume}=\frac{803g}{1L}  =803\frac{g}{L}

The required mass of fuel is 2.2 * 10⁴ kg, we can convert this value into g:

2.2 * 10⁴ kg * \frac{1000g}{1kg} = 2.2 * 10⁷ g

We calculate the required volume (V), using the mass and density:

803 g/L = \frac{2.2*10^{7}g }{V} \\V=\frac{2.2*10^{7}g }{803g/L}\\ V=27397.26 L

Thus 27,397.23 L would be needed for a successful trip.

5 0
4 years ago
A critical reaction in the production of energy to do work or drive chemical reactions in biological systems is the hydrolysis o
MAVERICK [17]

Answer : The value of \Delta G_{rxn} is -49.6 kJ/mol

Explanation :

First we have to calculate the reaction quotient.

Reaction quotient (Q) : It is defined as the measurement of the relative amounts of products and reactants present during a reaction at a particular time.

The given balanced chemical reaction is,

ATP(aq)+H_2O(l)\rightarrow ADP(aq)+HPO_4^{2-}(aq)

The expression for reaction quotient will be :

Q=\frac{[ADP][HPO_4^{2-}]}{[ATP]}

In this expression, only gaseous or aqueous states are includes and pure liquid or solid states are omitted.

Given:

[ATP] = 5.0 mM

[ADP] = 0.60 mM

[HPO_4^{2-}] = 5.0 mM

Now put all the given values in this expression, we get

Q=\frac{(0.60)\times (5.0)}{(5.0)}=0.60mM=0.60\times 10^{-3}M

Now we have to calculate the value of \Delta G_{rxn}.

The formula used for \Delta G_{rxn} is:

\Delta G_{rxn}=\Delta G^o+RT\ln Q    ............(1)

where,

\Delta G_{rxn} = Gibbs free energy for the reaction  = ?

\Delta G_^o =  standard Gibbs free energy  = -30.5 kJ/mol

R = gas constant = 8.314\times 10^{-3}kJ/mole.K

T = temperature = 37.0^oC=273+37.0=310K

Q = reaction quotient = 0.60\times 10^{-3}

Now put all the given values in the above formula 1, we get:

\Delta G_{rxn}=(-30.5kJ/mol)+[(8.314\times 10^{-3}kJ/mole.K)\times (310K)\times \ln (0.60\times 10^{-3})

\Delta G_{rxn}=-49.6kJ/mol

Therefore, the value of \Delta G_{rxn} is -49.6 kJ/mol

6 0
3 years ago
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