Answer:
a) 
b) 
is the limiting reagent
c) Moles of 
produced = 2.45 mol
b) Moles of 
left = 1.75 -1.22 = 0.53
Explanation:
a) Balanced reaction:
b)
No. of mole of 
No. of mole of 
As, it is clear from the reaction that,
1 mol of requires 3 moles of
1.75 mol of require = 1.75 × 3 = 5.25 mol of
As, only 3.68 mol of is present, so is the limiting reagent.
c)
3 moles of form 2 moles of 
3.68 moles of will form = 
d)
is present in excess.
3 moles of requires 1 mol of
3.68 moles of will require = 
left = 1.75 -1.22 = 0.53 mol
Answer:
Why do you like frogs?
Explanation:
(I dont mean that in a mean way I am just curious why)
39.25 g of water (H₂O)
Explanation:
We have the following chemical reaction:
2 H₂ + O₂ → 2 H₂O
Now we calculate the number of moles of each reactant:
number of moles = mass / molar weight
number of moles of H₂ = 14.8 / 2 = 7.4 moles
number of moles of O₂ = 34.8 / 32 = 1.09 moles
We see from the chemical reaction that 2 moles of H₂ will react with 1 mole of O₂ so 7.4 moles of H₂ will react with 3.7 moles of O₂ but we only have 1.09 moles of O₂ available. The O₂ will be the limiting reactant. Knowing this we devise the following reasoning:
if 1 moles of O₂ produces 2 moles of H₂O
then 1.09 moles of O₂ produces X moles of H₂O
X = (1.09 × 2) / 1 = 2.18 moles of H₂O
mass = number of moles × molar weight
mass of H₂O = 2.18 × 18 = 39.25 g
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limiting reactant
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