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Natali [406]
3 years ago
12

Determine the number of ions produced in the dissociation of the compound listed. BaS

Chemistry
2 answers:
11Alexandr11 [23.1K]3 years ago
4 0
BaS → Ba²⁺ + S²⁻
two types of ions
juin [17]3 years ago
3 0

Answer : The number of ions produced in the dissociation of the compound BaS are, two.

Explanation :

Dissociation reaction : It is defined as the chemical reaction in which a compound breaks into two or more ions.

The general representation of reaction is :

AB\rightarrow A+B

The dissociation reaction of the given compound will be,

BaS\rightarrow Ba^{2+}+S^{2-}

From the reaction we conclude that, there are two ion are produced in the dissociation of BaS compound which are, Ba^{2+} ion and S^{2-} ion.

Hence, the number of ions produced in the dissociation of the compound BaS are, two.

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A cube of an unknown metal is 1.25 inches on each side and has a mass of 128.3741 g. What is its' density?
Mademuasel [1]
Hey there!

To find the density of an object, you must use this formula:
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Knowing that your mass is 128.3741, the only information you need left would be to find the volume of the cube.

Because the side length of the cube is given, you can multiply the length three times in order to find its volume:
1.25*1.25*1.25
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The following solutions are prepared by dissolving the requisite amount of solute in water to obtain the desired concentrations.
Mama L [17]

Answer:

CaCl₂ > CH₃OH = LiCl > C₆H₁₂O₆

Explanation:

The osmotic pressure of a compound is calculated using the following expression:

π = MRT (1)

This expression is used when the substance is nonelectrolyte. If the solution is electrolyte solution then we need to count the van't hoff factor into the expression so:

π = MRTi  (2)

Now, we have 4 solutions here, only two of them are electrolyte solution, this means that these solutions can be dissociated into separate ions. These solutions are LiCl and CaCl₂. It can be shown in the following reactions:

LiCl -------> Li⁺ + Cl⁻     2 ions   (i = 2)

CaCl₂ ---------> Ca²⁺ + 2Cl⁻      3 ions (i = 3)

The methanol (CH₃OH) and glucose (C₆H₁₂O₆) are non electrolyte solutions, therefore they are not dissociated. So, let's use expression (1) for methanol and glucose, and expression (2) for the salts:

CaCl₂:   π = 1 * 3 * RT = 3RT

CH₃OH:   π = 2 * RT = 2RT

C₆H₁₂O₆:  π = 1 * RT = 1RT

LiCl: π = 1 * 2 * RT = 2RT

Finally with these results we can conclude that the decreasing order of these solutions according to their osmotic pressures are:

<h2>CaCl₂ > CH₃OH = LiCl > C₆H₁₂O₆</h2>
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3 years ago
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