Ok! So, given a quadratic function<span>, </span>y<span> = ax</span>2<span> + bx + c, when "a" is positive, the </span>parabola <span>opens upward and the vertex is the minimum value. On the other hand, if "a" is negative, the graph opens downward and the vertex is the maximum value. Now, let's refer back to our original graph, </span>y<span> = </span><span>x2</span><span>, where "a" is 1.
Hope this helps.</span>
Answer:42
Step-by-step explanation:
V= 18 + 6(4)
V= 18 + 24
V= 42
(g-h)(x) = 2x+1 -(<span>x-2)
</span>(g-h)(x) = 2x+1 - x + 2
(g-h)(x) = x + 3
S = sally C = Chris J = Joe
sally is one year older than 3 times the age of joe, so
s = 3j + 1
chris is 5 years younger than 6 times the age of jo, so
c = 6j - 5
sally and chris are the same age so
s = c so
3j + 1 = 6j - 5
-3j -3j
1 = 3j - 5
+5 +5
6 = 3j or
3j = 6
3j/3 = 6/3
j = 2
check
s = c
3(2) +1 = 6(2) - 5
6 + 1 = 12 - 5
7 = 7 correct✅
Answer:
Box A = 37.3333333333
Box B = 23.33333333333
Box C = 9.33333333333
Step-by-step explanation:
