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nikitadnepr [17]
2 years ago
13

Simplify the expression (7x + 5) - (2x - 4)

Mathematics
1 answer:
34kurt2 years ago
7 0

Answer: 17x+20

7x * 2x = 14x

5 * 4 = 20

14x + 3x = 17x

17x + 20

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The sum of three consective even integers if the largest number is y
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Step-by-step explanation:

If y is largest number, you want y, and the two next smaller even integers smaller than y - i.e. y, y-2, and y-4

The sum of these is y + (y-2) + (y-4).

This simplifies to 3y - 6 or 3(y - 2)

Since we don’t know what y is, this is as far as we can solve the problem.

6 0
2 years ago
Write an equation for the quadratic graphed below
uranmaximum [27]

Answer:

Step-by-step explanation:

LOL The graph doesn’t match the y intercept :)

Anyway

If we have point (0,-3) we have a quadratic of

y=ax^2+bx-3 we are given points (-1,0) and (2,0) so

a-b-3=0 and 4a+2b-3=0

4a+2b-3+2(a-b-3)=0

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6 0
3 years ago
Read 2 more answers
A car travels 17 miles on one gallon of gas
zmey [24]

When x =170, y =10, when x = 187, y = 1, when x = 204, y = 12, when x = 221, y = 13, when x = 238, y = 14, when x = 255, y = 15, when x = 272, y = 16, when x = 289, y = 17, when x = 306, y = 18, when x = 323, y = 19, when x = 340, y = 20,

Step-by-step explanation:

Step 1; Assume y is the gallons in the tank while x is the range of the car. We need to determine the equation relating the y to the x values in the given coordinates. x is the dependent value whereas y is the independent value i.e. the value of x depends on the value of y.

Step 2; As y increases, x also increases. For every extra gallon in the tank, the car can go another 17 miles. So with y as the amount of gas in the tank in gallons and x as the range of vehicle, we get;

x = 17y, this represents the relation between x and y.

To find the gallons in the tank, y = \frac{x}{17},

For x = 170, y = \frac{170}{17} = 10,

Similarly equating the values we get that when x = 187, y = 11,

when x = 204, y = 12,

when x = 221, y = 13,

when x = 238, y = 14,

when x = 255, y = 15,

when x = 272, y = 16,

when x = 289, y = 17,

when x = 306, y = 18,

when x = 323, y = 19,

when x = 340, y = 20,

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2 years ago
2х - 1y = 6<br> -Зу = -6х + 18
zysi [14]

Answer:2x-y-6=0 & 2x-y=6

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-3y=-6x+18.

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2x-y-6=0

7 0
3 years ago
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Ahmed wrote the two expressions below.
Vsevolod [243]
Put an equal sign between the two expressions, and solve for x
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