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dimulka [17.4K]
3 years ago
6

Simplified please SHOW WORK

Mathematics
1 answer:
jasenka [17]3 years ago
8 0

Answer:

sorry for blurred image........

Step-by-step explanation:

hope it helps

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I need help with question 3 part B please !
Alona [7]

Answer:

Yes, one inch is a twlefth of a ft which is a porportion of a feet

Step-by-step explanation:

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3 years ago
What is<br> is 1/4 + 9/10y -3/5y +7/8 written in simplest form?
Leviafan [203]

Answer:

Step-by-step explanation:

\frac{1}{4}+\frac{9}{10}y - \frac{3}{5}y+\frac{7}{8}\\\\=\frac{1}{4}+\frac{7}{8}+\frac{9}{10}y-\frac{3}{5}y\\\\

Combine like terms. 1/4 and 7/8 are like terms and LCD of 4 and 8 is 8

9/10y and -3/5y are like terms and LCD of 10 , 5 is 10

= \frac{1*2}{4*2}+\frac{7}{8}+\frac{9}{10}y-\frac{3*2}{5*2}y\\\\=\frac{2}{8}+\frac{7}{8}+\frac{9}{10}y-\frac{6}{10}y\\\\=\frac{9}{8}+\frac{3}{10}y

5 0
2 years ago
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EasyElectrics supermarket orders light bulbs from suppliers, AA Electronics and AAA Electronics. EasyElectrics purchases 30% of
saw5 [17]

Answer: (a) 0.006

               (b) 0.027

Step-by-step explanation:

Given : P(AA) = 0.3 and P(AAA) = 0.70

Let event that a bulb is defective be denoted by D and not defective be D';

Conditional probabilities given are :

P(D/AA) = 0.02 and P(D/AAA) = 0.03

Thus P(D'/AA) = 1 - 0.02 = 0.98

and P(D'/AAA) = 1 - 0.03 = 0.97

(a) P(bulb from AA and defective) = P ( AA and D)

                                                       = P(AA) x P(D/AA)

                                                       = 0.3 x 0.02 = 0.006

(b) P(Defective) = P(from AA and defective) + P( from AAA and defective)

                         = P(AA) x P(D/AA) + P(AAA) x P(D/AAA)

                         = 0.3(0.02) + 0.70(0.03)

                         = 0.027

3 0
3 years ago
Elizabeth’s aunt started a college savings account for her with $6,000. What is the balance of the account after 5 years if the
vaieri [72.5K]

Answer:

6750

Step-by-step explanation:

simple interest = P×r%×t

P = $6000

r = 2.5%

t = 5 years

I = 6000 × 2.5/100 × 5

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6000 + 750 = $6750

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2 years ago
The output of a flashlight is 2.0 x 10 lumens. If 1 lumen is about 1.464 x 10 3 watts, then
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