Help me fast pls, im on a test

What is the slope of the line on the graph?<br> Enter your answer in the box.

Firlakuza [10]

Answer:

I think this is the answer you are looking for. (See below)

Step-by-step explanation:

From the given graph it is noticed that the line is passing through many points.

The coordinates of three given points are (1,5), (-1,-1), (-1,-7)

If a line passing through two points (x1 ,y1) and (x2, y2) , the slope of the lie is defined by, m= y2 - y1/x2 - x1

The line passing through two points (-1,1) and (1,5). So the slope of the line is, m= 5 - 1 / 1 minus -1

m=4/2

Therefore, the slope of the line is 2.

Pls if this is wrong, let me know in the comments. I'm not really good at this topic in math but I hope it helps you. Sorry if it is wrong. Have a good day. :)

6 0

3 years ago

Solve this please show your work <3

Nookie1986 [14]

Given:

The expression is

$\sqrt[3]{48}=\sqrt[3]{8\cdot \_\_}=$

To find:

The simplified form of the expression.

Solution:

We have,

$\sqrt[3]{48}=\sqrt[3]{8\cdot \_\_}=$

The expression $\sqrt[3]{48}$ can be written as

$\sqrt[3]{48}=\sqrt[3]{8\cdot 6}$

$\sqrt[3]{48}=\sqrt[3]{8}\cdot \sqrt[3]{6}$ $[\because \sqrt[3]{ab}=\sqrt[3]{a}\sqrt[3]{b}]$

$\sqrt[3]{48}=2\cdot \sqrt[3]{6}$

$\sqrt[3]{48}=2\sqrt[3]{6}$

Therefore, $\sqrt[3]{48}=\sqrt[3]{8\cdot 6}=2\sqrt[3]{6}$ .

5 0

3 years ago

If you roll two six-faced dice together, you will get 36 possible outcomes. 4 pts 1. List all possible outcomes of the experimen

bezimeni [28]

Given:

Two dice are rolled together.

Total number of possible outcomes.

To find:

The list of total possible outcomes.

The probability of getting a sum of 11 in these outcomes.

The probability of getting a sum less than or equal to 4.

The probability of getting a sum of 13 or more.

Solution:

If two dice are rolled together, then the total number of possible outcomes is 36 and list of total possible outcomes is

S = {(1,1),(1,2),(1,3),(1,4),(1,5),(1,6),(2,1),(2,2),(2,3),(2,4),(2,5),(2,6),(3,1),(3,2),(3,3),(3,4),(3,5),(3,6),(4,1),(4,2),(4,3),(4,4),(4,5),(4,6),(5,1),(5,2),(5,3),(5,4),(5,5),(5,6),(6,1),(6,2),(6,3),(6,4),(6,5),(6,6)}

Sum of 11 in these outcomes = {(5,6),(6,5),(6,6)} = 3

The probability of getting a sum of 11 in these outcomes is

$P(\text{sum=11})=\dfrac{3}{36}$