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Masteriza [31]
3 years ago
14

I need help?????????

Mathematics
1 answer:
amid [387]3 years ago
3 0

Answer: I got D i'm not sure if that right though..

Step-by-step explanation:

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241 ten in base five?
igor_vitrenko [27]
  1. 241/5=48r1
  2. 48/5=9r3
  3. 9/5=1r4
  4. 1/5=0r4
  5. =4431
7 0
3 years ago
What are the zeros of the quadratic function f(x) = 6x^2 + 12x – 7?
irinina [24]
<span>6x^2 + 12x – 7 = 0

Use the quadratic formula:

x=  \frac{-b +/-  \sqrt{b^2 -4ac} }{2a}

\frac{-12+/- \sqrt{ 12^{2} -4(6)(-7)} }{12} = \frac{-12+/-17.66}{12}

x = 0.47 and x = -2.47
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3 0
3 years ago
Amy regularly works 20 hours per week at Pook's Dry Cleaners from Monday through Friday. She earns $15.50 per hour and receives
vladimir2022 [97]
15.50 x 20 = $310
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310 + 248 = $558
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8 0
3 years ago
A golfer takes two putts to get the ball into the hole. The first putt rolls the ball 10.3 feet in the northwest direction and t
creativ13 [48]

Let's put this on the usual Cartesian grid just so we can talk about it without drawing a picture.  We'll use map conventions, right is east, up is north.

The ball starts at (0,0).   10.3 feet northwest means we have an isosceles right triangle whose diagonal is 10.3 feet.  It's isosceles because northwest means equal parts north and west.   

The sides of these triangles are in ratio 1:1:\sqrt{2} so the coordinates after the first putt are

(- 10.3 / \sqrt{2}, 10.3 / \sqrt{2})

The negative sign indicates west, which doesn't really matter for this problem.  The distance from the origin to this point is 10.3 as required.

Now a second putt of 3.8 feet north puts us at
 
(- 10.3 / \sqrt{2}, 10.3 / \sqrt{2} + 3.8)

The squared distance to the origin is exactly

d^2 = 10.3^2/2 + (10.3 / \sqrt{2} + 3.8)^2

A little calculator work tells us

d \approx 13.2621

Third choice.



3 0
3 years ago
Answer asap
Gnom [1K]
Swap the n with the 7

7-5

Find the answer to 7-5

7-5=2

So the answer is 2
7 0
1 year ago
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