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Mashutka [201]
2 years ago
6

PUTTING MAX POINTS

Chemistry
2 answers:
Delicious77 [7]2 years ago
8 0
The first one is correct because one mole of oxygen is half of 2O2 so it is half of the energy


it absorbs because the negative sign indicates energy taken inside

hope this helps
coldgirl [10]2 years ago
4 0

the first one is correct because one mole of oxygen is half of 2O2 so it is half of the energy

You might be interested in
1. How many moles of nitrogen monoxide can be made using 5.0 moles of oxygen in
FrozenT [24]

Answer:

1)  <u>10.0 moles of NO</u>

<u>2) 25 moles of NaCl</u>

3) <u>1200 moles of CO2</u>

<u>4) 1.03 moles of MgO</u>

<u>5) 0.72 moles H2</u>

<u>6) 1041.15 grams BaCl2</u>

<u>7) </u>9.55 grams MgO

8) <u>45.5 grams Au</u>

<u>9 )14.93 grams AlCl3</u>

Explanation:

1. How many moles of nitrogen monoxide can be made using 5.0 moles of oxygen in the following composition reaction?

N2 + O2 → 2NO

For 1 mol N2 we need 1 mol O2 to produce 2 moles of NO

For 5.0 moles of N2 we need 5.0 moles of O2 to produce <u>10.0 moles of NO</u>

2. The neutralization of an acid with a base is a double replacement reaction in which a salt and water are formed. If you start with 25 moles of HCl and neutralize it with  NaOH how many moles of NaCl will be formed?

HCl + NaOH → NaCl + H2O

For 1 mol HCl we need 1 mol NaOH to produce 1 mol of NaCl and 1 mol H2O

For 25 moles of HCl we need 25 moles of NaOH to produce <u>25 moles of NaCl</u> and 25 moles of H2O

3. A car burns gasoline (octane – C8H18) with oxygen. If you drive to Salt Lake and  burn 150 moles of octane how many moles of carbon dioxide are you producing?

2C8H18 + 25O2 → 16CO2 + 18H2O

For 2 moles of octane we need 25 moles of O2 to produce 16 moles of CO2 and 18 moles of H2O

For 150 moles of octane we need 25*75 = 1875 moles of O2

To produce 16*75 = <u>1200 moles of CO2</u> and 18*75= 1350 moles

4. If 25 gram of magnesium combines with oxygen in a composition reaction, how  many moles of magnesium oxide will be formed?

2Mg + O2 → 2MgO

Moles of Mg = 25.0 g/24.3 g/mol = 1.03 moles

For 2 moles Mg we need 1 mol O2 to produce 2 moles MgO

For 1.03 moles Mg we'll have <u>1.03 moles of MgO</u>

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5. . Lithium reacts with water in a single replacement reaction. How many moles of  hydrogen gas a produced by 10 grams of lithium?

2Li + 2H2O → 2LiOH + H2

Moles Li = 10.0 grams/ 6.94 g/mol = 1.44 moles

For 2 moles Li we need 2 mole H2O to produce 2 moles LiOH and 1 mol H2

For 1.44 moles Li we need 1.44 moles H2O to produce 1.44 moles H2O and <u>0.72 moles H2</u>

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6. Barium chloride reacts with sodium sulfate in a double replacement reaction. How  many grams of barium chloride are required to react with 5 moles of sodium sulfate?

BaCl2 + Na2SO4 → BaSO4 + 2NaCl

For 1 mol of BaCl2 we need 1 mol of Na2SO4 to produce 1 mol of BaSO4 and 2 moles NaCl

For 5 moles Na2SO4 we need 5 moles BaCl2

mass BaCl2 = 5 moles * 208.23 g/mol = <u>1041.15 grams BaCl2</u>

7. Magnesium carbonate when heated decomposes to form magnesium oxide and carbon dioxide. How many grams of magnesium oxide will be formed if 20 grams of  magnesium carbonate are heated?

MgCO3 → MgO + CO2

Moles MgCO3 = 20.0 grams / 84.31 g/mol

Moles MgCO3 = 0.237 moles

For 1 mol MgCO3 we'll have 1 mol MgO and 1 mol CO2

For 0.237 moles MgCO3 we'll have 0.237 moles MgO and 0.237 moles CO2

Mass MgO = 0.237 moles * 40.30 g/mol = 9.55 grams MgO

8. If 70 grams of gold III chloride decomposes into its elements, how many grams of  gold will be produced?

2AuCl3 → 2Au + 3Cl2

Moles AuCl3 = 70 grams / 303.33 g/mol = 0.231 moles

For 2 moles AuCl3 we'll have 2 moles gold and 3 moles Cl2

For 0.231 moles AuCl3 we'll have 0.231 moles gold

Mass of gold =  0.231 moles * 196.97 g/mol = <u>45.5 grams Au</u>

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9. Chlorine is more reactive element than bromine, thus chlorine will replace bromine in compound through a single replacement reaction. If 30 grams of aluminum bromide react with chlorine in this fashion how many grams of aluminum chloride will be formed?

2AlBr3 + 3Cl2 → 2AlCl3 + 3Br2

Moles AlBr3 = 30 g /266.69 g/mol = 0.112 moles

For 2 moles AlBr2 we need 3 moles Cl2 to produce 2 moles AlCl3 and 3 moles Br2

For 0.112 moles AlBr3 we need 3/2 * 0.112 = 0.168 moles of Cl2

To produce 0.112 moles of AlCl3 and 0.168 moles of Br2

Mass AlCl3 = 0.112 moles * 133.34 g/mol = <u>14.93 grams AlCl3</u>

8 0
3 years ago
When writing the chemical formulas for a molecular compound, what method do you use?​
podryga [215]

Answer:

A molecular compound is usually composed of two or more nonmetal elements. Molecular compounds are named with the first element first and then the second element by using the stem of the element name plus the suffix -ide.

4 0
2 years ago
If 3.89 × 1024 atoms of a noble gas is collected and it has a mass of of 848 grams, this element is most likely a. He b. Ne c. A
bearhunter [10]

Answer:

Xenon

Explanation:

Avogadro’s number represent the number of the constituent particles which are present in one mole of the substance. It is named after scientist Amedeo Avogadro and is denoted by N_0.

Avogadro constant:-

N_a=6.023\times 10^{23}

Let the molar mass of the element is x g/mol

So,

6.023\times 10^{23} atoms have a mass of x g

Also,

3.89\times 10^{24} atoms have a mass of \frac{x}{6.023\times 10^{23}}\times 3.89\times 10^{24} g

This mass is equal to 848 g

So,

\frac{x}{6.023\times 10^{23}}\times 3.89\times 10^{24}=848

x= 131.3 g/mol

This mass correspond to xenon.

3 0
3 years ago
An equilibrium mixture of O2, SO2 and SO3 contains equal concentrations of SO2 and SO3.
AleksAgata [21]

Answer:

[O₂(g)] = 0.0037M

Explanation:

            2SO₂(g) + O₂(g) => 2SO₃(g)

Conc:   [SO₂(g)]   [O₂(g)]     [SO₃(g)]  and  [SO₂(g)] = [SO₃(g)]

Kc =  [SO₃(g)]²/[O₂(g)][SO₂(g)]² => Kc = 1/[O₂(g)] = 270 if [SO₂(g)] = [SO₃(g)]

∴ [O₂(g)] = (1/270)M = 0.0037M  

7 0
3 years ago
What is the molar mass of MnP
igomit [66]

The production of manganese peroxidase (MnP) by Irpex lacteus, purified to electrophoretic homogeneity by acetone precipitation, HiPrep Q and HiPrep Sephacryl S-200 chromatography, was shown to correlate with the decolorization of textile industry wastewater. The MnP was purified 11.0-fold, with an overall yield of 24.3%. The molecular mass of the native enzyme, as determined by gel filtration chromatography, was about 53 kDa. The enzyme was shown to have a molecular mass of 53.2 and 38.3 kDa on SDS-PAGE and MALDI-TOF mass spectrometry, respectively, and an isoelectric point of about 3.7. The enzyme was optimally active at pH 6.0 and between 30 and 40 degrees C. The enzyme efficiently catalyzed the decolorization of various artificial dyes and oxidized Mn (II) to Mn (III) in the presence of H(2)O(2). The absorption spectrum of the enzyme exhibited maxima at 407, 500, and 640 nm. The amino acid sequence of the three tryptic peptides was analyzed by ESI Q-TOF MS/MS spectrometry, and showed low similarity to those of the extracellular peroxidases of other white-rot basidiomycetes.

5 0
3 years ago
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