Answer:
NaCl
Explanation:
none of them. Salt presents NaCl
Answer:
Molarity of a solution that contains 3.11 mol of NaNO3 is 1,24 M
Explanation:
We understand molarity as the number of moles of solute that are contained in 1 L of solution, then if in a solution of 2.50 L we have 3.11 moles, it remains to calculate how many moles do we have in 1 liter.
2,50 L .......... 3,11 moles
1 L .................. x
X = ( 1 L x 3,11 moles) / 2,50 L = 1,24
The correct answer for this question is 'False'
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Answer:
A
Explanation:
195.49 g K x 1 mole / 39.01 g x 6.022 x 10^23 atoms/mole = 30.11 x 10^23 = 3.011 x 10^24
Answer:
19.27
Explanation:
Some values are corrected from correct source.Thus,
Moles of SO₂ = 8.19x10⁻² moles
Moles of O₂ = 8.10x10⁻² moles
Volume = 1 L
Concentration of SO₂ = 8.19x10² M
Concentration of O₂ = 8.10x10 M
Considering the ICE table for the equilibrium as:
2SO₂ (g) + O₂ (g) ⇔ 2SO₃ (g)
t = o 8.19x10⁻² 8.19x10⁻²
t = eq -2x -x 2x
---------------------------------------------
--------------------------
neq: 8.19x10⁻² -2x 8.19x10⁻²
-x 2x
Given:
Equilibrium concentration of O₂ = 5.98x10⁻² M = 8.19x10⁻²
-x
Thus, x = 0.0212 M
[SO₂] = 8.19x10⁻² - 2*0.0212 = 0.0395 M
[SO₃] = 2*0.0212 = 0.0424 M
The expression for the equilibrium constant is:
![K_c=\frac {[SO_3]^2}{[SO_2]^2[O_2]}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%20%7B%5BSO_3%5D%5E2%7D%7B%5BSO_2%5D%5E2%5BO_2%5D%7D)
K = 19.27
