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2 years ago

How to solve this problem 15 = 5x

Mathematics

1 answer:

Lostsunrise [7]2 years ago

4 0

Answer:

x = 3 (see below)

Step-by-step explanation:

To solve for x, you need to isolate the variable to one side of the equation. To do that, you need to use reverse operations. For example, the reverse operation of subtraction is addition.

In this case, we have:

15 = 5x

5x is the same thing as 5 (x) or 5 times x. This means the reverse operation is division. So, we need to divide both sides of the equation by 5:

15 = 5x

----- ----

5 5

--------------

3 = x

x = 3

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A fruit company delivers its fruit in two types of boxes: large and small. A delivery of

Tema [17]

Answer:

Small box weighs 13.75 kg & large box weighs 15.75 kg

Step-by-step explanation:

We can write 2 simultaneous equation and solve for weight of each box.

Let weight of large box be l and small box be s.

"3 large boxes and 5 small boxes has a total weight of 116 kilograms":

$3l+5s=116$

and

"9 large boxes and 7 small boxes has a total weight of 238 kilograms":

$9l+7s=238$

Now we can solve for l in the 1st equation and put it into 2nd equation and get s:

$3l+5s=116\\3l=116-5s\\l=\frac{116-5s}{3}$

now,

$9l+7s=238\\9(\frac{116-5s}{3})+7s=238\\3(116-5s)+7s=238\\348-15s+7s=238\\348-238=15s-7s\\110=8s\\s=\frac{110}{8}=13.75$

now we plug in 13.75 into s into equation of l to find s:

$l=\frac{116-5s}{3}\\l=\frac{116-5(13.75)}{3}\\l=15.75$

5 0

2 years ago

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arlik [135]

Answer:

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3 years ago

Which choice is equivalent to the expression below? 2sqrt(7) + 8sqrt(7)

dexar [7]

Answer:

Dear Twinkie

Answer to your query is provided below

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5 0

3 years ago

Consider the following equation. f(x, y) = y3/x, P(1, 2), u = 1 3 2i + 5 j (a) Find the gradient of f. ∇f(x, y) = Correct: Your

BaLLatris [955]

$f(x,y)=\dfrac{y^3}x$

a. The gradient is

$\nabla f(x,y)=\dfrac{\partial f}{\partial x}\,\vec\imath+\dfrac{\partial f}{\partial y}\,\vec\jmath$

$\boxed{\nabla f(x,y)=-\dfrac{y^3}{x^2}\,\vec\imath+\dfrac{3y^2}x\,\vec\jmath}$

b. The gradient at point P(1, 2) is

$\boxed{\nabla f(1,2)=-8\,\vec\imath+12\,\vec\jmath}$

c. The derivative of $f$ at P in the direction of $\vec u$ is

$D_{\vec u}f(1,2)=\nabla f(1,2)\cdot\dfrac{\vec u}{\|\vec u\|}$

It looks like

$\vec u=\dfrac{13}2\,\vec\imath+5\,\vec\jmath$

so that

$\|\vec u\|=\sqrt{\left(\dfrac{13}2\right)^2+5^2}=\dfrac{\sqrt{269}}2$

Then

$D_{\vec u}f(1,2)=\dfrac{\left(-8\,\vec\imath+12\,\vec\jmath\right)\cdot\left(\frac{13}2\,\vec\imath+5\,\vec\jmath\right)}{\frac{\sqrt{269}}2}$

$\boxed{D_{\vec u}f(1,2)=\dfrac{16}{\sqrt{269}}}$

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3 years ago

Simplify 20+4(3)÷(-8)

Mashcka [7]

The answer to this problem would be 12. If you need to show work just comment.

4 0

2 years ago

Read 2 more answers