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tiny-mole [99]
2 years ago
5

How to solve this problem 15 = 5x

Mathematics
1 answer:
Lostsunrise [7]2 years ago
4 0

Answer:

x = 3 (see below)

Step-by-step explanation:

To solve for x, you need to isolate the variable to one side of the equation. To do that, you need to use reverse operations. For example, the reverse operation of subtraction is addition.

In this case, we have:

15 = 5x

5x is the same thing as 5 (x) or 5 times x. This means the reverse operation is division. So, we need to divide both sides of the equation by 5:

15 = 5x

-----   ----

5       5

--------------

3 = x

x = 3

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Answer:  See Below

<u>Step-by-step explanation:</u>

NOTE: You need the Unit Circle to answer these (attached)

5) cos (t) = 1

Where on the Unit Circle does cos = 1?

Answer: at 0π (0°) and all rotations of 2π (360°)

In radians:     t = 0π + 2πn

In degrees:   t = 0° + 360n

******************************************************************************

6)\quad sin (t) = \dfrac{1}{2}

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<em>Hint: sin is only positive in Quadrants I and II</em>

\text{Answer: at}\  \dfrac{\pi}{6}\ (30^o)\ \text{and at}\ \dfrac{5\pi}{6}\ (150^o)\ \text{and all rotations of}\ 2\pi \ (360^o)

\text{In radians:}\ t = \dfrac{\pi}{6} + 2\pi n \quad \text{and}\quad \dfrac{5\pi}{6} + 2\pi n

In degrees:    t = 30° + 360n  and  150° + 360n

******************************************************************************

7)\quad tan (t) = -\sqrt3

Where on the Unit Circle does    \dfrac{sin}{cos} = \dfrac{-\sqrt3}{1}\ or\ \dfrac{\sqrt3}{-1}\quad \rightarrow \quad (1,-\sqrt3)\ or\ (-1, \sqrt3)

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In degrees:    t = 120° + 360n  and  300° + 360n

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Answer:

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Answer: See explanation

Step-by-step explanation:

Your question isn't really clear. Let me help you rephrase it and solve.

Let's say Cesar is creating a schedule to practice his instrument for band. He needs to practice for a total of 10 hours in a week. On Monday he practice for 1 1/2 hours, on Tuesday he practiced for 2 1/4 hours, and on Wednesday he practiced for 1 1/2 hours.

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Cesar needs to practice for 4 3/4 hours more.

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{ explained in image}

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