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ladessa [460]
3 years ago
14

Find the volume of a sphere that has diameter of 9 feet.

Mathematics
1 answer:
jek_recluse [69]3 years ago
5 0

Answer:

V≈381.7ft³

Step-by-step explanation:

try using a sphere calculator next time its a lot easier and saves time

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The slope of the line whose equation is 3x - 2y = 4 is 2/3 3/2 -2
7nadin3 [17]

Answer:

3/2

Step-by-step explanation:

The equation 3x-2y=4 can be written in the form of y=mx+c where m is the slope and c is the y intercept.

Therefore

2y=3x-4 and dividing both sides by 2 to have y at the LHS

y=3/2x-2

Therefore, 3/2 represents the gradient/slope

6 0
3 years ago
5x + 2 = 3x + 4(2x - 1)<br><br> show steps
LUCKY_DIMON [66]

Answer:

x=1

Step-by-step explanation:

5x+2=3x+4(2x-1)

5x+2=3x+8x-4

5x+2=11x-4

5x-11x=-4-2

-6x=-6

6x=6

x=1

7 0
2 years ago
Need help please math questions # 12 and 14
icang [17]

Answer:

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
A highway department executive claims that the number of fatal accidents which occur in her state does not vary from month to mo
den301095 [7]

This question is incomplete, the complete question;

A highway department executive claims that the number of fatal accidents which occur in her state does not vary from month to month. The results of a study of 193 fatal accidents were recorded. Is there enough evidence to reject the highway department executive's claim about the distribution of fatal accidents between each month? Month Jan Feb Mar Apr May Jun Jul Aug Sep Oct Nov Dec Fatal Accidents 11 13 22 11 15 29 15 9 13 15 22 18

Step 10 of 10 : State the conclusion of the hypothesis test at the 0.1 level of significance.

Answer: H₀ : The distribution of fatal accidents between each month is same

Step-by-step explanation:

H₀ : The distribution of fatal accidents between each month is same

H₁ : The distribution of fatal accidents between each month is different

Let the los be alpha 0.10

given data ;

       Observed    Expected  

Mon   Freq (Oi)   Freq Ei       (Oi-Ei)^2 /Ei

Jan      11    16.0833        1.606649

Feb      13    16.0833        0.591105

Mar      22    16.0833        2.176598

Apr       11    16.0833        1.606649

May     15    16.0833        0.072971

Jun     29    16.0833        10.373489

Jul     15    16.0833        0.072971

Aug       9    16.0833        3.119603

Sep      13    16.0833        0.591105

Oct      15    16.0833        0.072971

Nov      22    16.0833        2.176598

Dec      18    16.0833       0.228411

Total:   193     93                22.689119

Expected Freq ⇒ 193 / 12 = 16.08333

Test Statistic, x² : 22.6891

Num Categories: 12

Degrees of freedom: 12 - 1 = 11

Critical value X² : 24.725

P-Value: 0.0195

since Chi-square value < Chi-square critical value

and P-value > alpha 0.01 so we accept H₀

Therefore we conclude that the distribution of fatal accidents between each month is same

7 0
3 years ago
Solve for xxx.<br> Your answer must be simplified.<br> 15 &lt; -5 x
katrin [286]

Answer:

x<−3

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
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