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ladessa [460]
3 years ago
14

Find the volume of a sphere that has diameter of 9 feet.

Mathematics
1 answer:
jek_recluse [69]3 years ago
5 0

Answer:

V≈381.7ft³

Step-by-step explanation:

try using a sphere calculator next time its a lot easier and saves time

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the figure shows the dimensions of a room in which receptions are held. The room is being carpeted. The three semi-circular part
mars1129 [50]

Answer:

258.39 m^2

Step-by-step explanation:

Solve for the rectangle:

18 • 12= 216

Now solve for the 3 semi circles:

A = 3.14(3)^2= 28.26/2 = 14.13 •3 = 42.39

Add up the areas:

216 + 42.39 = 258.39

8 0
3 years ago
Only number 6. ‍ ‍ ‍ ‍ ‍ ‍ ‍
djverab [1.8K]
The answer is 6, 4 divided by 2/3 =6
if you need to show your work just multiply by the reciprocal :)
6 0
3 years ago
Please help.. will mark brainlyiest
irina1246 [14]

Answer:

B. Dog 1's position is Dog 2's position reflected across the x-axis; only the signs of the y-coordinates of Dog 1 and Dog 2 are different.

Step-by-step explanation:

First it is reflected on the x-axis because it is above and below. if its was the y-axis (which it is not) it would be side to side, if that makes sense.

Secondly the x values are the same, they are both -6. So, the y values are the ones that are different.

5 0
3 years ago
In a designated VIP seating section there must be an odd number of seats in each row and each row must have two more seats than
Vikki [24]

Let n be the total number of rows and there are x seats is the 1st row where x is an odd natural number.

As each row must have 2 more seats than the one before it, so

Number of seats in 2nd row = x+2

Number of seats in 3rd row = x+2+2=x+2x2

Number of seats in 4th row = x+2+2+=x+2x3

Similarly, the number of seats in (n-1)th row =x+2x(n-1)

the number of seats in n^{th} row, i.e last row  =x+2x n.

As the front row must have one-quarter of the total seats in the back 2 rows combined, so

x =\frac 1 4 ( x+2\times(n-1) + x+2\times n) \\\\\Rightarrow 4x=2x+4n-6 \\\\\Rightarrow 4x-2x=4n-6 \\\\\Rightarrow 2x=4n-6 \\\\\Rightarrow x=2n-3\cdots(i)

So, the number of seats in the 1st row, x, and the total number of seats, n, must satisfy the equation (i).

For x>0, n\geq 3.

So, for n=3 rows

The number of seats in the 1st row, x= 2x3-3=3.

The number of seats in the 2nd row, = 3+2=5 as in subsequent rows, there will be 2 more seats.

and the number of seats in the 3rd row (last row)=5+2=7.

n can have any integral values satisfying  n\geq 3.

3 0
3 years ago
A sound receiving dish used at outdoor sporting events is constructed in the shape of a paraboloid, with its focus 8 inches from
bixtya [17]

Answer:

w≅8.46ft

Step-by-step explanation:

Data

focus=8

vertex=(0,0)

width=?

depth (y)=3ft

parabola equation: (x-h)^{2}=4p(y-k); then for V=(0,0), x^{2} =4py, be focus(f)=8in;  x^{2} =4*8*y=32y → y=\frac{x^{2} }{32}

we have that y=3ft then 3=\frac{x^{2} }{32}; but 1in≅0.083ft so x^{2} =3*32*0.083=7.968 → x=±2.82, finally w=3*2.82≅8.46ft

6 0
3 years ago
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