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2 years ago

Which of the following theorems cannot be used to prove two lines are parallel?

Mathematics

1 answer:

mariarad [96]2 years ago

6 0

Answer:

Option H

Step-by-step explanation:

Option F

If two lines are cut by a transversal so that a pair of corresponding angles are congruent, then the lines are parallel.

True.

Option G

If two lines are cut by a transversal so that a pair of alternate exterior angles are congruent, then the lines are parallel.

True

Option H

If two line are cut by a transversal so that a pair of vertical angles are congruent, then the lines are parallel.

Since, vertical angles don't prove the lines cut by a transversal are parallel.

So the statement is False.

Option J

If two lines are are cut by a transversal so that a pair of same side interior angles are supplementary, then the lines are parallel.

True.

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If G( x ) = 3 x + 1, then G -1 (1) is...<br><br> -1/3<br> -4<br> -0

GarryVolchara [31]

Answer:

-4

Step-by-step explanation:

3+1 = 4 so just put a dash at the start and you ger -4

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2 years ago

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The answer is b) 8.625.

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2 years ago

Read 2 more answers

Find the slope of each line from the graph.

Sunny_sXe [5.5K]

Answer:

a. 1/2

b. 5/3

c. 0

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Step-by-step explanation:

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2 years ago

The Coopers own two vehicles, a mini-van and sedan. The following functions represent the resale value of both cars, in thousand

velikii [3]

Answer:

$h(x) = 57(0.8)^x$

Step-by-step explanation:

Given

$f(x) = 32(0.8)^x$

$g(x) = 25(0.8)^x$

Required

A function that represents the total resale value of the two vehicles

To do this, we simply add up the functions

$h(x) = f(x) + g(x)$

$h(x) = 32(0.8)^x + 25(0.8)^x$

Factorize

$h(x) = (32 + 25)(0.8)^x$

$h(x) = 57(0.8)^x$

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2 years ago

Please Please Help Me In These Math Questions!!!!’

Harman [31]

Answer:

m∠JLN = 42°

m∠MLK = 90°

m∠KLO = 42°

m∠JLO = 138°

m∠AGE = 160°

Step-by-step explanation:

m∠JLN = $90-48=42$ °

m∠MLK = 90°

m∠KLO = 42° (∠KLO opposite of ∠JLN, Opposite angles are congruent)

m∠JLO = $180-42=138$ °

For the second question, things become somewhat more complex.

We know that ∠GHD = $2x$ ° and ∠AGH $(x+15)$ °.

You correctly calculated that $x=15$ °.

∠AGE is equal to both $180-(x+15)$ ° and $180-2x$ °. Either equation will work just fine.

∠AGE = $180 - (15 + 15) = 180 - 30 = 160$ °

So m∠AGE = 160°

6 0

2 years ago