Two numbers that gives twice the sum of a number and 3 times a second number is 4. The difference of ten times the second number and five times the first is 90 are -10 and 4
Given :
Twice the sum of a number and 3 times a second number is 4. The difference of ten times the second number and five times the first is 90.
Let a and b be the two unknown numbers
Lets frame equation using the given statements
Twice the sum of a number and 3 times a second number is 4.

the difference of ten times the second number and five times the first is 90

Now use these two equations to solve a and b

Add both the equations

Now find out 'a'

The two numbers are -10 and 4
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Answer:
she will need to get a 100 on the fourth test
Step-by-step explanation:
(252+x)/4 = 88
252+x = 352
x = 100
Answer:
Step-by-step explanation:
-14 + 2x + 3 = 4x - 13 - 7x
We can first add the numbers and coefficients on either side:
2x - 11 = -3x - 13
Then, we can add 3x to both sides:
5x - 11 = -13
We can add 11 to both sides
5x = -13 + 11 = -2
Lastly, we can divide both sides by 5
x = -2 / 5
Answer:
I cant see the photo
Step-by-step explanation:
sorry