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3 years ago

26=4v+3v+12 can anyone help?

Mathematics

2 answers:

motikmotik3 years ago

4 0

Answer:

Step-by-step explanation:

Combine like terms

3v + 4v

26=7v+12

Subtract 12 from both sides of the equation

26-12

12-12

14=7v

Simplify

so subtract the 12's

Divide both sides of the equation by the same term

14 divided by 7

7 divided by 7

Simplify

do the division and move the term on the other side and it would be

v=2

Solution

v=2

elixir [45]3 years ago

3 0

Answer:

v = 2

Step-by-step explanation:

1. Combine like terms.

26 = 4v + 3v + 12

26 = 7v + 12

2. Subtract 12 from both sides of the equation.

26 = 7v + 12

26 - 12 = 7v + 12 - 12

3. Simplify.

·Subtract the numbers

14 = 7v

4. Divide both sides of the equation by the same term.

14 = 7v

14/7 = 7v/7

5. Simplify

·Divide the numbers

·Cancel terms that are in both the numerator and denominator

·Move the variable to the left

v = 2

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Classify the number as rational or irrational.

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Have a nice day!

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3 years ago

Read 2 more answers

The life of a red bulb used in a traffic signal can be modeled using an exponential distribution with an average life of 24 mont

BartSMP [9]

Answer:

See steps below

Step-by-step explanation:

Let X be the random variable that measures the lifespan of a bulb.

If the random variable X is exponentially distributed and X has an average value of 24 month, then its probability density function is

$\bf f(x)=\frac{1}{24}e^{-x/24}\;(x\geq 0)$

and its cumulative distribution function (CDF) is

$\bf P(X\leq t)=\int_{0}^{t} f(x)dx=1-e^{-t/24}$

• What is probability that the red bulb will need to be replaced at the first inspection?

The probability that the bulb fails the first year is

$\bf P(X\leq 12)=1-e^{-12/24}=1-e^{-0.5}=0.39347$

• If the bulb is in good condition at the end of 18 months, what is the probability that the bulb will be in good condition at the end of 24 months?

Let A and B be the events,

A = “The bulb will last at least 24 months”

B = “The bulb will last at least 18 months”

We want to find P(A | B).

By definition P(A | B) = P(A∩B)P(B)

but B⊂A, so A∩B = B and

$\bf P(A | B) = P(B)P(B) = (P(B))^2$

We have

$\bf P(B)=P(X>18)=1-P(X\leq 18)=1-(1-e^{-18/24})=e^{-3/4}=0.47237$

hence,

$\bf P(A | B)=(P(B))^2=(0.47237)^2=0.22313$

• If the signal has six red bulbs, what is the probability that at least one of them needs replacement at the first inspection? Assume distribution of lifetime of each bulb is independent

If the distribution of lifetime of each bulb is independent, then we have here a binomial distribution of six trials with probability of “success” (one bulb needs replacement at the first inspection) p = 0.39347

Now the probability that exactly k bulbs need replacement is

$\bf \binom{6}{k}(0.39347)^k(1-0.39347)^{6-k}$

Probability that at least one of them needs replacement at the first inspection = 1- probability that none of them needs replacement at the first inspection.

This means that,

Probability that at least one of them needs replacement at the first inspection =

$\bf 1-\binom{6}{0}(0.39347)^0(1-0.39347)^{6}=1-(0.60653)^6=0.95021$

5 0

3 years ago

write the ratio as a percent 6 per 100 , 49 out of 100 , 16 per 100 , 21 out of 100 , 80 per 100 , 93 out of 100

DedPeter [7]

Answer:

6%, 49%, 16%, 21%, 80%, 93%

Step-by-step explanation:

add the percent sign to each each number (6, 49, 16, 21, 80, and 93).

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3 years ago

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Brian is solving the equation x squared minus three-fourths x = 5. What value must be added to both sides of the equation to mak

Allushta [10]

Answer:

StartFraction 9 Over 64 EndFraction

Step-by-step explanation:

He must add the square of half the x coefficient. That coefficient is 3/4, so half of it is 3/8 and the square of that is ...

(3/8)^2 = 9/64

Brian mus add 9/64 to boths sides of the equation.

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3 years ago

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State the requirements that must be satisfied to use the one-way ANOVA procedure. Select all that apply. A. The k samples must

Sergeu [11.5K]

Answer:

The correct option are: (A), (B), (C) and (E).

Step-by-step explanation:

The One-Way ANOVA is a statistical test used to compare the three or more population means.

The hypothesis is:

H₀: The population means are equal, i.e. μ₁ = μ₂ = μ₃ =...= μₙ

Hₐ: At least one of the population mean differ.

The Assumptions of One-way ANOVA are:

The samples selected from each population are independent of each other.
The population distribution of the dependent variables follow Normal distribution.
The population variances are always equal for all the groups.

Thus, the correct option are: (A), (B), (C) and (E).

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2 years ago