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pshichka [43]
2 years ago
8

In a rectangle diagonal is 5cm ,breadth is 3cm .find the area and perimeter  of the rectangle? (STEP BY STEP EXPLANATION)​

Mathematics
1 answer:
DerKrebs [107]2 years ago
3 0

Answer:

The area of rectangle is 12cm² and the perimeter is 14cm.

Step-by-step explanation:

First, you have to find the length of the rectangle using Pythagoras Theorem :

a² + b² = c²

a² + 3² = 5²

a² = 5² - 3²

a² = 16

a = √16

a = 4 cm

Next, you have to find the perimeter and area of rectangle :

Perimeter = 2(length + breadth)

P = 2(4 + 3)

P = 2(7)

P = 14 cm

Area = length×breadth

A = 4×3

A = 12 cm²

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Answer:

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Area of a rectangle = L × W

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When a diagonal line divides a rectangle into 2 right angled triangles, the diagonal line = Hypotenuse of either of the triangle and it is the longest side.

The formula for a right angle triangle =

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We are told in the question that:

A diagonal between opposite corners is measured to be 10 ft longer than one side of the parcel

Let us assume the side that the hypotenuse is longer than = Width

Hence, the Diagonal = (W + 10)²

Therefore

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Since L = 6000/W

W² + (6000/W)² = (W + 10)²

W² + (6000/W)² = (W + 10) (W + 10)

W² + (6000/W)² = W² + 10W + 10W + 100

W² + (6000/W)² = W² + 20W + 100

W² - W² + (6000/W)² = 20W+ 100

6000²/W² = 20W + 100

6000² = W²( 20W + 100)

6000² = 20W³ + 100W²

20W³ + 100W² - 6000² = 0

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Since the Width = 120 feet

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