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mezya [45]
3 years ago
13

A polynomial function has a root of -6 with multiplicity 1, a root of -2 with multiplicity 3, a root of 0 with multiplicity 2, a

nd a
root of 4 with multiplicity 3. If the function has a positive leading coefficient and is of odd degree, which statement about
the graph is true?
O The graph of the function is positive on (-6, -2).
O The graph of the function is negative on (-0, 0).
O The graph of the function is positive on (-2, 4).
O The graph of the function is negative on (4.co).
Mathematics
1 answer:
skelet666 [1.2K]3 years ago
3 0

9514 1404 393

Answer:

  (a)  the graph is positive on (-6, -2)

Step-by-step explanation:

The roots, left to right, are ...

  -6, -2, 0, 4

The odd-multiplicity roots, where the sign changes, are ...

  -6, -2, 4

The function is negative to the left of -6, and positive to the right of +4. It is positive on the interval (-6, -2) and negative on the intervals (-2, 0) and (0, 4).

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Shiloh and her friends spent the day at an amusement park. In the first hour, they rode two rides. After 2 hours, they had ridde
solmaris [256]

Answer:

The function will be: f(n) = 2n

Step-by-step explanation:

An arithmetic sequence is a sequence where the common difference between consecutive terms is same

The sequence according to given information is:

2,4,6...

Here

a_1 = 2

a_2 = 4

a_3 = 6

the common difference will be:

d = a_2-a_1 = 4-2 = 2\\d = a_3-a_2 = 6-4 = 2

The arithmetic sequence is given by:

a_n = a_1+(n-1)d

Putting the values

a_n = 2+(n-1)(2)\\a_n = 2+2n-2\\a_n = 2n

Hence,

The function will be: f(n) = 2n

4 0
3 years ago
For the points in the table, does pressure vary directly with volume? If so, identify k and write an equation. No, this is not a
wel
Can't see the table but direct variation is: y = kx
So if the output is some constant multiple which could be positive, negative or fraction then yes it is direct variation. So just divide a couple y/x = k to see what you get.
7 0
3 years ago
Read 2 more answers
What is the average value of latex: y=\tan\left(\frac{x^2}{9}\right) y = tan ⁡ ( x 2 9 ) on the closed interval [1.25, 2]?
german
For this case we have the following function:
 f(x) =  tan(\frac{x^2}{9})
 The average rate of change is given by:
 AVR =  \frac{f(x2) - f(x1)}{x2- x1}
 Evaluating the function for the given interval we have:
 For x = 1.25:
 f(1.25) = tan(\frac{1.25^2}{9})
 f(1.25) = 0.18
 For x = 2:
 f(2) = tan(\frac{2^2}{9})
 f(2) = 0.48
 Then, replacing values we have:
 AVR = \frac{0.48 - 0.18}{2 - 1.25}
 AVR = 0.4
 Answer:
 
the average value of on the closed interval [1.25, 2] is:
 
AVR = 0.4



3 0
3 years ago
Select the correct answer.
vagabundo [1.1K]

Answer

D.  `(y+4) = (5)/(3)(x+ 1)`


Step by step explanation

The given points are (-1, -4) and (2, 1)

Slope = (y2 - y1)/(x2 - x1)

= (1 - (-4)) / (2 - (-1))

= (1 + 4) / (2 +1)

m = 5/3

When two points are given, the equation of the line is

(y - y1) = m (x - x1)

y -(-4) = 5/3 (x - (-1))

y + 4 = 5/3 (x + 1)

The answer is (y+4) = (5)/(3)(x+ 1)

Thank you.

5 0
3 years ago
Read 2 more answers
Point K is located at (7,4) in the coordinate plane. Its image is created by the following rule:
Fynjy0 [20]

We are given coordinate of K point (7,4).

We need to find the new coordinate of K' point.

Given rule is K' = Ro 270°^(k).

That represents rotation of k 270 degree about the origin.

<em>The rule for rotation of 270 degree about the origin is as following:</em>

<em>(x, y) --------> (y, -x).</em>

Now, applying same rule on point (7,4).

(7,4)  -----------> (4,-7).

<h3>Therefore, the coordinates of k' is (4,-7).</h3><h3>Correct option is A. (4,-7).</h3>
6 0
3 years ago
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