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aksik [14]
3 years ago
10

What is the slope of the line passing through the points (1, –5) and (4, 1)?

Mathematics
2 answers:
torisob [31]3 years ago
4 0
The slope is positive 2
MakcuM [25]3 years ago
3 0
The slope would be -2 because you would use the equation m= y2-y1/x2-x1
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Which of the following show an element of the sample space for first rolling a die and then tossing a coin?
Sphinxa [80]
A because if you use T3 it wouldn’t have make sense so only reasonable and solution that works is A
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miv72 [106K]
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6 0
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 For the equation 2n - 3 = 7
Stells [14]

Answer:

The variable is n

The coefficient is 2

And the solution to n is 10.

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The number in the equation is the variable. The coefficient is the number before the variable. And a number next to a letter means you multiply. So 2*5=10 10-3=7

5 0
2 years ago
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Graph y = 3x - 3 and label the x- and y-intercepts. My answer: (0,3)
Lesechka [4]
The slope-intercept form of the linear function is y = m x + b , where m is the slope and b is y-intercept.
Here we have: y = 3 x - 3
a ) When y = 0
0 = 3 x - 3
- 3 x  = - 3
x = ( - 3 ) : ( - 3 ) 
x = 1
When x = 0
y = 3 * 0 - 3 
y = - 3
So x - intercept is ( 1, 0 ) and y-intercept is ( 0, - 3 ).
b ) The slope:
m = ( y2 - y1) / ( x2 - x1 ) = 
= ( - 3 - 3 ) / ( 5- 7 ) = ( - 6 ) /( - 2 ) = 6 / 2 = 3
Answer: The slope m = 3 . 
5 0
2 years ago
3. Solve the system using elimination (not substitution or matrices). negative 2 x plus y minus 2 z equals negative 8A N D7 x pl
riadik2000 [5.3K]

Elimination Method

\begin{gathered} -2X+Y-2Z=-8 \\ 7X+Y+Z=-1 \\ 5X+2Y-Z=-9 \end{gathered}

If we multiply the equation 3 by (-1) we obtain this:

\begin{gathered} -2X+Y-2Z=-8 \\ 7X+Y+Z=-1 \\ -5X-2Y+Z=9 \end{gathered}

If we add them we obtain 0, therefore there are infinite solutions. So, let's write it in terms of Z

1. Using the 3rd equation we can obtain X(Y,Z)

\begin{gathered} 5X=-9-2Y+Z \\ X=\frac{-9-2Y+Z}{5} \\  \end{gathered}

2. We can replace this value of X in the 1st and 2nd equations

\begin{gathered} -2\cdot(\frac{-9-2Y+Z}{5})+Y-2Z=-8 \\ 7\cdot(\frac{-9-2Y+Z}{5})+Y+Z=-1 \end{gathered}

3. If we simplify:

\begin{gathered} \frac{-9Y+12Z-63}{5}=-1 \\ \frac{9Y-12Z+18}{5}=-8 \end{gathered}

4. We can obtain Y from this two equations:

\begin{gathered} Y=-\frac{-12Z+58}{9} \\  \end{gathered}

5. Now, we need to obtain X(Z). We can replace Y in X(Y,Z)

\begin{gathered} X=\frac{-9-2Y+Z}{5} \\ X=\frac{-9-2(-\frac{-12Z+58}{9})+Z}{5} \end{gathered}

6. If we simplify, we obtain:

X=\frac{-3Z+7}{9}

7. In conclusion, we obtain that

(X,Y,Z) =

(\frac{-3Z+7}{9},-\frac{-12Z+58}{9},Z)

8 0
10 months ago
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