$σ = \sqrt{ \frac{Σ{(xi - μ)}^{2} }{N} } \\ where \: σ = population \: standard \: deviation \\ xi = each \: value \: from \: population \\ μ = population \: mean \\ N = size \: of \: population$

$σ = \sqrt{ \frac{Σ{(9 - 26)}^{2} + {(16 - 26)}^{2} +{(30 - 26)}^{2} +{(35 - 26)}^{2} + {(40 - 26)}^{2}}{5} } \\ σ = \sqrt{ \frac{Σ{((-17)}^{2} + {(- 10) }^{2} +{(4) }^{2} +{(9) }^{2} +{(14) }^{2})}{5}} \\ σ = \sqrt{ \frac{Σ ({289} + {100} +{16} +{81} + {196})}{5} } \\ σ = \sqrt{ \frac{682}{5} } \\ σ = \sqrt{136.4} \\ σ = 11.679041056525\\ σ = 11.68$

4 0

3 years ago

Evaluate y5 for y = 1.<br> 1<br> 5<br> 15

Sauron [17]

IF you mean y^5, then your answer will be 1
if you mean y(5), then your answer will be 5

hope this helps

8 0

3 years ago

I really need help with this one. I’ll give u brainliest

zaharov [31]

Answer

248

I think :P

4 0

2 years ago

Read 2 more answers

One number is 2 less than a second number. Twice the second number is 5 less than 3 times the first. Find the two numbers.

Evgen [1.6K]

Answer:

9 and 11

Step-by-step explanation:

First number = x -2

Second number = x

and 2x = 3(x-2) - 5

2x = 3x - 6 - 5

x = 11

first number = 11-2 = 9

8 0

2 years ago